Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
, we have,
If the discriminant is greater than 
, we get complex roots.
Answer:
(2,5)
Step-by-step explanation:
[7+(-3)]/2 = 2
(8+2)/2 = 5
Answer: 1, 3
Step-by-step explanation:
Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.
Answer:
For the system of equations to be unique, s can take all values except 2 and -2
Step-by-step explanation:
![\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2s%264%5C%5C2%26s%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%20%5C%5C6%20%5Cend%7Barray%7D%5Cright%5D)
For the system to have a unique solution, 
For how many years?
In any case I will give you the formula & you will plug into the number of years"
Remaining Value (or Salvage Value) = initial cost(1 - rate%)^n(number of years
Remaining value after n years = 15000(1-23%)^n
