Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
Answer:
2.5
Step-by-step explanation:
i did it and got it right
1. Divide both sides by 4 = 1/2
2. Divide both sides by 4 = 1/3
3. Divide both sides by 3 = 1/3
4. Divide both sides by 2 = 1/2
5. Divide both sides by 3 = 4/5
