Question

How much 0.075 M NaCl solution can be made by diluting 450 mL of 9.0 M NaCl?

Answer 1

Answer:

54 L

Explanation:

Given data

• Initial concentration (C₁): 9.0 M

• Initial volume (V₁): 450 mL

• Final concentration (C₂): 0.075 M

• Final volume (V₂): to be calculated

We have a concentrated NaCl solution and we will add water to it to obtain a diluted NaCl solution. We can find the volume of the final solution using the dilution rule.

$C_1 \times V_1 = C_2 \times V_2\\V_2 = \frac{C_1 \times V_1}{C_2} = \frac{9.0M \times 450mL}{0.075M} = 5.4 \times 10^{4} mL = 54 L$