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liubo4ka [24]
3 years ago
5

What is the initial position of the object?

Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

e:10 m   b: -5 m/s b.The object decreases its velocity.

Explanation:

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daser333 [38]
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this is what happens with the planets. they go in a straight line, but since there’s gravity, the planets are also being pulled towards the sun. so gravity and inertia are why the planets orbit in the circle pattern they do. so when we remove inertia, we’re removing the state in which the planets keep going straight while being pulled towards a center point (the sun). this causes gravity to be the only factor in the planets orbiting. so that being said, the planets would just be pulled towards the sun. :)
4 0
3 years ago
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PLZZZZZZZZZZ HELP QUICK!!!!!!!!!!!!
kifflom [539]
In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀

where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â

Since d = 2 · r, we can write:
d = n² · d₀
   = 15² · 1.06
   =  238.5 Â

Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
8 0
3 years ago
Do you think the amount of positive charge on the glass after rubbing it with silk cloth will be equal to the amount of negative
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5 0
3 years ago
A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed
stich3 [128]

Answer:

Distance of closest approach, r=1.91\times 10^{-14}\ m

Explanation:

It is given that,

Charge on proton, q_p=e

Charge on alpha particle, q_a=2e

Mass of proton, m_p=1.67\times 10^{-27}\ kg

Mass of alpha particle, m_a=4m_p=6.68\times 10^{-27}\ kg

The distance of closest approach for two charged particle is given by :

r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}

r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}

r=1.91\times 10^{-14}\ m

So, their distance of closest approach, as measured between their centers 1.91\times 10^{-14}\ m. Hence, this is the required solution.

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3 years ago
What is the force exerted by a solid surface that opposes gravity?
jonny [76]

Electromagnetic force between the molecules! 
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4 years ago
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