The wavelength of the light is 590nm
wavelength of the light=λ
Given,
The equation for a diffraction grating to use here is dsinθ = mλ
d=1/610 lines per mm=1.639*
, m=1, θ=21.
λ=1.639* * sin21./1 =590nm
<h3>Wavelength </h3>
The wavelength, which in physics refers to the length over which a periodic wave repeats, is its spatial period. It is the distance between two successive corresponding wave points of the same phase, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling waves and standing waves, as well as other spatial wave patterns. The spatial frequency is defined as the wavelength's inverse. The Greek letter lambda, or "wavelength," is frequently used to represent it. Additionally, sinusoidal wave envelopes, modulated waves, and waves created by the interference of several sinusoids are also commonly referred to as having a wavelength.
You measure an angle of 21. 1 when the light passes through a grating with 610 lines per mm. what is the wavelength of the light?
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Ok so basically I’m here for the points cuz I gotta quiz do in 10 minutes sorry
Answer:
100 J, 225 J
Explanation:
The kinetic energy of an object is given by:
where
m is the mass of the object
v is the velocity of the object
In this problem, the initial kinetic energy of the object is
K = 25 J
Then, the velocity is doubled, which means
v' = 2v
Therefore, the new kinetic energy will be
Therefore, the kinetic energy has quadrupled:
Later, the velocity is tripled, which means
v'' = 3v
Therefore, the new kinetic energy will be
Therefore, the kinetic energy has increased by a factor of 9:
There are many factors which contributes as to how a machine will be processing the input energy and convert it to output energy. Even with identical mechanism, these factors will have major effect on the output. Some factors are deflection, friction and wear. Some system maybe exposed to poor lubrication than the other which'll produce more friction and wear thus lower mechanical advantage.
