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ElenaW [278]
3 years ago
8

Instantaneous angular speed is: Group of answer choices the rate at which the angular acceleration is changing total angular dis

placement divided by time the integral of the displacement over time the magnitude of the instantaneous angular velocity a vector directed along the axis of rotation
Physics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer: magnitude of the instantaneous angular velocity

Explanation:

Instantaneous angular speed is refered to as the magnitude of the instantaneous angular velocity. We should note that the instantaneous angular velocity is the rate that has to do with the rotation of an object in circular path.

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White dwarfs, the energy will all be used and it will begin to shrink.
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On an aircraft carrier, a jet can be catapulted from 0 to 240
IRISSAK [1]

Answer:

m = 27752.7 [kg]

Explanation:

To solve this problem we must first use the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 240 [km/h]

Vo =  initial velocity = 0

a = acceleration [m/s²]

t = time = 2 [s]

But first we must convert the speed from kilometers per hour to meters per second.

240[\frac{km}{h} ]*(\frac{1h}{3600s} )*(\frac{1000m}{1km} )=66.67[m/s]

Now replacing:

66.67 = 0 +a*2\\a = 33.33 [m/s^{2} ]

Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.

∑F = m*a

925000=m*33.33\\m = 925000/33.33\\m = 27752.7 [kg]

4 0
3 years ago
Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.
kramer

Answer:

The velocity of the proton is 2.965*10^{8} \frac{m}{s}

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

4,96*10^{-19} =1.6726*10^{-27} *vv=\frac{4.9*10^{-19} }{1.6726*10^{-27} }

v=(\frac{4.96}{1.6726} )*(10^{27-19} )

v=2,965*10^{8} m/s

Answer: The velocity of the proton is 2.965*10^{8} \frac{m}{s}

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F=ma (c) Newton, 2d Law
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I think it’s B I’m so right
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