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3 years ago

I really need help with this

Mathematics

1 answer:

vova2212 [387]3 years ago

8 0

The correct answer to this question is B.

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For each ordered pair (x,y) , determine whether it is a solution to the inequality

Leviafan [203]

The answer are below, the work is show step by step.

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4 years ago

in this truss bridge,△ABC ~△XYZ.based on the given information,what is AB? A)7m , B)14m , C)21m , D)28m

SIZIF [17.4K]

Answer:

i Belive the answer is going to be B

4 0

3 years ago

Read 2 more answers

Last Wednesday, a random sample of 24 students were surveyed to find how long it takes to walk from the Fretwell Building to the

Ray Of Light [21]

Answer:

Step-by-step explanation:

Solution:-

- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.

- The survey team took a sample of size n = 24 students and obtained the following results:

Sample mean ( x^ ) = 12.3 mins

Sample standard deviation ( s ) = 3.2 mins

- The sample taken was random and independent. We can assume normality of the sample.

- First we compute the critical value for the statistics.

- The z-distribution is a function of two inputs as follows:

Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025

Compute: z-critical = z_0.025 = +/- 1.96

- The confidence interval for the population mean ( u ) of walking times is given below:

[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]

Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]

3 0

3 years ago

A store marks up sweaters by 23%. Find the retail price of a sweater originally priced at<br>$48.

34kurt

Answer:

The mark up price of the sweater would be $59.04

8 0

3 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

4 years ago

I really need help with this​

I really need help with this