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Lera25 [3.4K]
3 years ago
5

The greater the mass of an object

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
6 0
The greater the mass of an object, the greater<span> its gravitational force.
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Plz chose as brainliest answer plz :)  <#



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Room temperature is usually considered to be 25°C. What is that in kelvins?
kotegsom [21]

Answer:

298.15 K.

Explanation:

Room temperature is generally taken to be 25 °C (around 77 °F). 0 °C is equivalent to 273.15 K, so we add 273.15 to 25 to find that room temperature is around 298.15 K

5 0
3 years ago
Which can occur in a physical change?<br> The mass can increase
solong [7]
In a physical change the form changes or the state of the matter. For instance water can freeze and water can melt, but it is still water.

Please vote my answer brainliest! Thanks.
3 0
3 years ago
A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
What is the mass of ether(0.71) which can be put into a beaker holding 130ml
UkoKoshka [18]
D=m/v    ⇒ m=d*v

d=density
m=mass
v=volume

d(ether)=0.71 gr/cm³=0.71 gr/ ml
v=130 ml

m=d*v
m=0.71 gr/ml*(130 ml)=92.3 g

Solution: m=92.3 g
6 0
3 years ago
What are 2 ways a mixture defers from a compound
grin007 [14]
Well a mixture is less permanent and also it can be easily taken aprt where a compound does the opposite of those things. 

Hope I helped :)
6 0
3 years ago
Read 2 more answers
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