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Genrish500 [490]
3 years ago
8

11) To approach a runway, a pilot must begin a 10° descent

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

the plane 2.2 miles away from the runway

Step-by-step explanation:  

Given the data in the question and as illustrated in the image below;

from the image, using trigonometric ratio;

SOH CAH TOA

sin = opposite / hypotenuse

sin10° = 0.38 / x

xsin10° = 0.38

x = 0.38 / sin10°

x = 0.38 / 0.173648

x = 2.1883 miles  ≈ 2.2 miles     { the nearest tenth of a mile }

Therefore, the plane 2.2 miles away from the runway

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cestrela7 [59]
First we find the slope by using the slope formula : (y2 - y1) / (x2 - x1)

slope = (y2 - y1) / (x2 - x1)
(0,7)....x1 = 0 and y1 = 7
(8,-2)...x2 = 8 and y2 = -2
now sub...pay attention to ur signs
slope = (-2 - 7) / (8 - 0) = -9/8

now we use y = mx + b
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u can use either of ur points...(0,7)...x = 0 and y = 7
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3 years ago
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Step-by-step explanation:

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2 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

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\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

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where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

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Tpy6a [65]

Answer:

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Step-by-step explanation:

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vesna_86 [32]

Answer: -1 because - 13 - 11 will = -1

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2 years ago
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