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3 years ago

11) To approach a runway, a pilot must begin a 10° descent

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer:

the plane 2.2 miles away from the runway

Step-by-step explanation:

Given the data in the question and as illustrated in the image below;

from the image, using trigonometric ratio;

SOH CAH TOA

sin = opposite / hypotenuse

sin10° = 0.38 / x

xsin10° = 0.38

x = 0.38 / sin10°

x = 0.38 / 0.173648

x = 2.1883 miles ≈ 2.2 miles { the nearest tenth of a mile }

Therefore, the plane 2.2 miles away from the runway

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Read 2 more answers

The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 3.6 cars and a

Iteru [2.4K]

Answer:

$X \sim N(3.6,5)$

Where $\mu=3.6$ and $\sigma=5$

Then we have:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

With the following parameters:

$\mu_{\bar X}= 3.6$

$\sigma_{\bar X} = \frac{5}{\sqrt{100}}= 0.5$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the number of cars running a red light of a population, and for this case we know the distribution for X is given by:

$X \sim N(3.6,5)$

Where $\mu=3.6$ and $\sigma=5$

Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by: