Answer:
Its the first one (top left option)
Step-by-step explanation:
ur in a rush so i wont explain, pls give me brainliest
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Nothing crazy here, just a matter of figuring out the limits of integration.
Answer:
Explanation:
The row for month 25 shows that after <em>twenty-five payments</em> <u>the balance of the loan is $10,356.03</u>
You are told that the<em> loan amount or principal is $ 19,900</em>.
From those two data, you can calculate <em>how much of the principal has been paid off after </em>25 months, because the amount paid off is equal to the loan less the balance after 25 payments:
- Principal paid off = $ 19,900 - $ 10,356.03 = $9,543.97
