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3 years ago

Under state law, what is the blood-alcohol limit for legally operating a motor vehicle?

Physics

1 answer:

Ymorist [56]3 years ago

5 0

Answer:

HOPE IT HELPS....

Explanation:

CORRECT ANSWER IS 0.08

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a runner increases her speed from 3.1 m/s to 3.5 m/s during the last 15 seconds of her run, what was her acceleration during her

Rama09 [41]

Acceleration = velocity/time
A= 3.5m/s/15s
A= 0.23m/s^2

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3 years ago

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which fire extinguisher is most appropriate to put out a fire that involves a stack of burning newspapers

evablogger [386]

Monoammonium phosphate effectively smothers the fire, while sodium bicarbonate induces a chemical reaction which extinguishes the fire. Fire extinguishers with a Class C rating are suitable for fires in “live” electrical equipment.

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3 years ago

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if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?

Katena32 [7]

A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.

In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.

Learn more about harmonics here brainly.com/question/17315536

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2 years ago

A central air conditioner in a typical American home operates on a 220-V circuit and draws about 15 A

Zepler [3.9K]

Answer:

Find answers below.

Explanation:

Given the following data;

Voltage = 220V

Current = 15 A

a. To find the power;

Power = current * voltage

Power = 15 * 220

Power = 3300 Watts

b. To find the energy;

Time = 8 hours = 60 * 60 * 8 = 28800 seconds

Energy = power * time

Energy = 3300 * 8

Energy = 26400

Energy = 26.4 Kwh

c. Cost = 13 cents

Cost = 13 * 31 * 26.4

Cost = 106392 cents

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3 years ago

The Jurassic Park ride at Universal Studios theme park drops 25.6 m straight down essentially from rest. Find the time for the d

ankoles [38]

Answer:

V=22.4m/s;T=2.29s

Explanation:

We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:

$mgh=\frac{1}{2}mv^{2}\\\\X= V_{0}t-\frac{gt^{2}}{2}$

Solving for velocity using equation 1:

$mgh=\frac{1}{2}mv^{2} \\\\gh=\frac{v^{2}}{2}\\\\\sqrt{2gh}=v\\\\v=\sqrt{2*9.8\frac{m}{s^2}*25.6m}=22.4\frac{m}{s}$

Solving for time in equation 2:

$-25.6m = 0\frac{m}{s}t-\frac{9.8\frac{m}{s^{2}}t^{2}}{2}\\\\-51.2m=-9.8\frac{m}{s^{2}}t^{2}\\\\t=\sqrt{\frac{51.2m}{9.8\frac{m}{s^{2}}}}=2.29s$

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3 years ago