Answer:
Correct answer: A.) V = - 16.6 m/s down
Explanation:
Given:
V₀ = 3 m/s initial velocity
t = 2 seconds
g = 9.8 m/s²
V(t) = V(2) = ?
The movement described is a vertical upward shot
For velocity at any time is valid the next formula
V = V₀ - g · t
V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down
Under condition that it has a enough drop height with respect to the ejection point.
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The total electrostatic force on charge A is 
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
Here we have three positively charged particles A,B and C, located at the following positions:
The magnitudes of the three charges are:
The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:
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Answer:
0.480 seconds
Explanation:
The period is the time for 1 revolution. Writing a proportion:
14.4 s / 30.0 rev = t / 1 rev
t = 0.480 s
The period is 0.480 seconds.
If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects
<u>Answer:</u>
increases
Explanation:
The formula of gravitational force is given as:
F=G Mm/r^2
G = gravitational constant
M, m = Masses of two different objects in which the force is acting.
r = distance between both the objects.
As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.
When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.
Illamends had the exact same answer from a similar question. Credit goes to her
