According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:

where F is the magnitude of the force, m is the mass of the object and a its acceleration.
In this problem, the object is the insect, with mass

. The acceleration of the insect is

, therefore we can calculate the force exerted by the car on the insect:

How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.
Answer:
D. Sound Energy, Magnetic energy
Explanation:
Sound energy is in motion, and Magnetic energy is about to be in motion.
It is about 100oC at a pressure of 1.1 atmosphere. Hope this helps.
I believe the correct answer would be kimberlite. Diamonds are usually found in pipes 50 to 200 m across made of kimberlite. It is an igneous rock that is known to contain traces of diamonds. It is named base on the town where it was discovered which is Kimberley, South Africa.

Heat capacity of body 1 :

Heat capacity of body 2 :

it's given that, the the head capacities of both the objects are equal. I.e


Now, consider specific heat of composite body be s'
According to given relation :



[ since,
]




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