Answer:
Explanation:
The answer is D- The number of flies decreased, then leveled off.
Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
Answer:
The decrease of these factors increases the acceleration.
Explanation:
Hi, the decrease of these factors increases the acceleration.
Air resistance is a force opposing the acceleration. So if it decreases, the acceleration increases, because the opposite forces decreases.
The same is applied to the force of gravity, since the rocket travels upward; gravity is also an opposite force.
Finally, if the mass decreases, it means that the rocket becomes lighter and the force acting on the smaller mass causes an increase in the acceleration.
Answer:
Explanation:
We shall consider direction towards left as positive Let the required velocity be v and let v makes an angle φ
Applying law of conservation of momentum along direction of original motion
m₁ v₁ - m₂ v₂ = m₂v₃ - m₁ v₄
0.132 x 1.25 - .143 x 1.14 = 1.03 cos43 x .143 - v cos θ
v cos θ = .8
Applying law of conservation of momentum along direction perpendicular to direction of original motion
1.03 sin 43 x .143 = .132 x v sinθ
v sinθ = .76
squaring and adding
v² = .76 ² + .8²
v = 1.1 m /s
Tan θ = .76 / .8
θ = 44°
