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2 years ago

What is the equivalent resistance?

Physics

1 answer:

mote1985 [20]2 years ago

7 0

Answer:

C 3.33 Ω

Explanation:

From the equation given 1 / Rtot = 1/10 + 1/5 = 3/10

then Rtot = 10/3 = 3.33 Ω

As an aside:

When there are only two resistors in parallel, the equivalent R is

= R1*R2 / (R1 + R2) = 10*5 / (10+5) = 50 / 15 = 3.33 Ω

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A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. How much energy is lost? Group of answer choices 0.5

bogdanovich [222]

Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J

Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.

<h3>What is gravitational potential energy?</h3>

The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
The gravitational potential energy of a body at a height h with respect to the height h will be,

$U=mgh$

Expression for gravitational potential energy loss will be,

$E=U_i-U_f$

<h3>How to solve the problem?</h3>

The total energy before the ball dropped will be,

$U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J$

The total energy after when the ball rebounds to 1.5m will be,

$U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J$

The total energy loss will be,

$E=1.176-0.882=0.294J$

Thus, we can conclude that, the energy loss will be,0.294J.

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1 year ago

a 320-foot tree casts a 130-foot shadow on horizontal ground. a girl lying on the grass at the tip of the shadow is looking at a

mixer [17]

Answer: $\theta =67.88^{\circ}$

Explanation:

Given

Height of tree is H=320 ft

length of shadow L=130 ft

let $\theta$ be the angle of elevation

using trigonometric relation

$\tan \theta =\frac{H}{L}$

$\tan \theta =\frac{320}{130}$

$\theta =tan^{-1}(2.461)$

$\theta =67.88^{\circ}$

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2 years ago

During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of

Phantasy [73]

Answer:

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Explanation:

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$m_2$ = Mass of performer = 65 kg

$u_1$ = Initial Velocity of cannon ball = 8 m/s

$u_2$ = Initial Velocity of performer = 0 m/s

v = Velocity of combined mass

As the linear momentum of the system conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{29\times 8 + 65\times 0}{29 + 65}\\\Rightarrow v=2.4681\ m/s$

The recoil velocity is 2.4681 m/s

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3 years ago

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Crank

Answer:

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The best place where coal beds can form is in a swamp.

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2 years ago

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Pepsi [2]

Answer:

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2 years ago

What is the equivalent resistance?​

What is the equivalent resistance?