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kiruha [24]
3 years ago
13

The perimeter of a rectangle is 34 units. It’s width is 6.5 units

Mathematics
2 answers:
rjkz [21]3 years ago
8 0
The length on the side is 10.5
Papessa [141]3 years ago
4 0

Answer:

The length for on side is 10.5.

Step-by-step explanation:

6.5 + 6.5 = 13

34 - 13 = 21

21 divided by 2 is 10.5

Length 10.5 + 10.5 + 6.5 + 6.5 = 34

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Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,
Sholpan [36]
A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

7 0
2 years ago
Find sin theta in the given triangle​
lana [24]
Sin = surd 3 / 2

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7 0
2 years ago
The length of a rectangle is 4 less than twice the width. If the perimeter of the rectangle is 130, find the length of the recta
Alchen [17]

Answer:

Let L be the length of the rectangle and w be the width of the rectangle.

"The lenght of a rectangle is one less than twice the width" means L=2W-1

Using perimeter formula of a rectangle which is P=2(L+W) you have:

P=2(L+W)

130=2(2W-1+W)

Solve equation above to find W

130=2(3W-1)

130=6W-2

130+2=6W

132=6W

W=22

From here you find L=2W-1=2x22-1=43

Only thing left is to find area A=LxW

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3 years ago
Stacy and Travis are rock climbing. Stacy’s rope is 4 feet shorter the 3 times the length of Travis rope. Stacy’s rope is 23 fee
prohojiy [21]
23×3=69
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7 0
3 years ago
What is the range of f(x)=43*2.4^x
Aliun [14]
This is an exponential function.
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7 0
3 years ago
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