All categories

3 years ago

Solve the expression

Mathematics

1 answer:

bogdanovich [222]3 years ago

4 0

Answer:

y - 12 = 89

y - 12 + 12 = 89 + 12

y = 101

You might be interested in

Please help me with this question

Amanda [17]

The graph shows the maximum residual is ...
◉ Data point (10, 10); Residual = 4.50

_____
Apparently, this question makes no use of the line of best fit.

6 0

3 years ago

Which points are on the the graph equation -3x+6y+5=-7

algol [13]

-3x + 6y + 5 = -7
 -5 -5
 -3x + 6y = -12
-3x + 3x + 6y = -12 + 3x
 6y = -12 + 3x
 6 6
 y = -2 + 1/2x
-3x + 6(-2 + 1/2x) = -12
 -3x - 12 + 3x = -12
 -3 + 3x - 12 = -12
 0x - 12 = -12
 +12 +12
 0x = 0
 0 0
 x = 0
 -3(0) + 6y = -12
 0 + 6y = -12
 +0 +0
 6y = -12
 6 6
 y = -2
 (x, y) = (0, -2)

6 0

4 years ago

Plz help can anybody solve this only one question

stiks02 [169]

Step-by-step explanation:

Angle:2x+30+3x=180

Angle:2x+b+2b=180( Being in straight line)

Angle:30+3x+a=180

5 0

3 years ago

Line segment ab has endpoints a(9, 3) and b(2, 6). find the coordinates of the point that divides the line segment directed from

Dominik [7]

When we are to divide the line segment such that the ratio is 1:2, there are actually 3 parts of the segment. First, we determine the distance between the coordinates and divide the distance by 3. Then, we add the quotient to the x-coordinate.

x-coordinate: (2 - 9) / 3 = -7/3
y-coordinate: (6 - 3 ) / 3 = 1

Adding them to the coordinates of a,
x - coordinate: (9 - 7/3) = 20/3
y - coordinate: (3 + 1) = 4
Thus, the coordinates are (20/3, 4).

7 0

4 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago