Answer:
c. reduces the concentration of the hazardous material in the air.
Explanation:
Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.
Particulate population is a form of pollution that is responsible for the degradation of the environment.
Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air. Other forms of particle pollution includes space debris and marine debris.
Some examples of particulate pollution are dusts, soot, dirt, smoke, etc.
Basically, various anthropogenic activities such as construction and agriculture are primary sources of particulate matter because they're capable of causing particle pollution on their own. The other sources of particle pollution is the secondary source which includes factories, cars, trucks, etc.
Vapor dispersion can be defined as a process which is typically used for removing particle pollutants from the atmosphere through the use of vapor or steam.
Hence, vapor dispersion when adopted, reduces the concentration of the hazardous material such as soot, dusts, smoke, etc., in the air.
Answer:
1.93
Explanation:
Moles of C
H
COOH = 38/1000 × 0.50 = 0.019mol
Moles of CHCOONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol
Final pH = pKa + log([CHCOONa]/[CHCOOH]
= -log Ka + log(mols of CHCOONa]/mols of CHCOOH
= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17
change in pH = final - initial pH
= 4.17 - 2.24
=1.93
Answer:
The final temperature of water = 35.2 °C
Explanation:
Step 1: Data given
Mass of C6H6 = 8.100 grams
Mass of water = 5691 grams
Temperature = 21 °C
Step 2: The balanced equation
2C6H6(l) + 15O2(g) ⟶ 12 CO2 (g) + 6H2O (l) + 6542 kJ
Step 3:
Q = m*c*ΔT.
⇒with Q = the heat released during this reaction (this depends on the amount of reactants used)
⇒
with m= the mass of the water
⇒with c = the "specific heat" of water = how much energy it takes to raise the temp of 1g of water by 1°C
⇒with ΔT = the change in the temperature of the water
For every 2 moles of C6H6 consumed, 6542 kJ of heat is released.
Step 4: Calculate moles for 8.100 grams
8.100grams / 78.11 g/mol= 0.1037 mol
es
So, according to the equation, the amount of heat released is:
(0.1037 moles / 2 moles)* (6542 kJ) = 339.2 kJ
Step 5: Calculate the final temperature
Q = mcΔT
ΔT = Q / (m*c)
T2- T1 = Q / (m*c)
T2 = [Q / (m*c)] + T1 = [(339.2 kJ) / (5691g)(0.004186 kJ/g°C)] + 21°C = 35.2°C
The final temperature of water = 35.2 °C
<span> strictly speaking, a molecule has at least two atoms. ... Atoms with full valence electron shells are stable. Full Text[ edit ] The noble gases are a group of chemical elements that make up Group 18 on the periodic table.</span>
Answer:
C. C and Pb
Carbon and Lead being in the same group.
