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Fed [463]
3 years ago
10

How many independent variables can be tested in a standard scientific experiment

Chemistry
1 answer:
Shalnov [3]3 years ago
6 0

One independent variable

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In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False
Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .          

sodium potassium move 3Na+ outside the cells          

and  moving 2k+ inside the cells                        

so that we can say that given statement is false    

Answer FALSE                                                      

6 0
2 years ago
If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?
qwelly [4]
To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT  where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15 
V = 189.98 L
7 0
3 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
2 years ago
Whats 2736 +832091 +09281
astra-53 [7]

844108

One way is to write down all the numbers and add and write down each number.

5 0
3 years ago
calculate the mass required to prepare 2.5 L of 1.0 M NaOH solution. Given that the molar mass for NaOH is 40 g/mol.
Helen [10]

Answer:

The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g

Explanation:

We do this by preparing the equation:

Mass = concentration (mol/L) x volume (L) x Molar mass

Mass = 1.0 M x 2.5 L x 40 g/mol

Mass = 100 g

3 0
2 years ago
Read 2 more answers
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