<u>A. reaction A: chemical; reaction B: nuclear</u>
Answer:
Solution given:
as
Circle 2: Reaction B
-Involves neutrons
-Happens inside atomic nucleus
-Releases relatively large amounts of energy
<u>I</u><u>t</u><u> </u><u>h</u><u>a</u><u>p</u><u>p</u><u>e</u><u>n</u><u>s</u><u> </u><u>o</u><u>n</u><u> </u><u>n</u><u>o</u><u>r</u><u>m</u><u>a</u><u>l</u><u> </u><u>c</u><u>h</u><u>e</u><u>m</u><u>i</u><u>c</u><u>a</u><u>l</u><u> </u><u>reaction</u><u>.</u>
Circle 2: Reaction B
-Involves neutrons
-Happens inside atomic nucleus
-Releases relatively large amounts of energy
<u>I</u><u>t</u><u> </u><u>h</u><u>a</u><u>p</u><u>p</u><u>e</u><u>n</u><u>s</u><u> </u><u>o</u><u>n</u><u> </u><u>n</u><u>u</u><u>c</u><u>l</u><u>e</u><u>a</u><u>r</u><u> </u><u>r</u><u>e</u><u>a</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u>.</u>
Liquid - takes the shape of the container and maintains volume
Solid- maintain shape
True, for example, hydrogen peroxide (liquid):
H₂O₂ + H₂O ⇄ H₃O⁺ + HO₂⁻
HO₂⁻ + H₂O ⇄ H₃O⁺ + O₂²⁻
(the resulting solution is weakly conducting)
Answer:
Half-reactions:
Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻
Net ionic equation:
2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺
Explanation:
The Cr³⁺ is reduced to Cr²⁺:
<h3>
Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>
Zn is oxidized to Zn²⁺:
<h3>
Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>
Twice the reduction of Cr:
2Cr³⁺ + 2e⁻ → 2Cr²⁺
Now this reaction + Oxidation of Zn:
2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻
<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>
The answer is 1.03 quarts
