hey there!:
2HgO (s) => 2Hg (l) + O2 (g)
2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.
So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.
603 g of Hg = 603 / 200.6 = 3 moles
Percent yield = ( actual yield / theoretical yield) * 100
= ( 3/4) * 100
= 75 %
Hope this helps!
Answer:The lowest value of n that allows g orbitals to exist is 5.
Answer:
It produces magnesium oxide and hydrogen gas.
Explanation:
When magnesium burns with steam it produces magnesium oxide which is white in color and hydrogen gas. When magnesium burns, it mixes with the oxygen present in the air produces magnesium oxide in powder form. Magnesium react with oxygen by giving two electrons present in its valance shells while the oxygen needs two electron for completing their valance shell and becomes stable.
<u>Answer:</u> The empirical formula for the given compound is 
<u>Explanation:</u>
We are given:
Mass of pure compound containing copper and sulfur = 4.963 g
Mass of S = 1.000 g
Mass of Cu = (4.963 - 1.000) g = 3.963 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Copper =
Moles of Sulfur = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.
For Copper = 
For Sulfur = 
<u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of Cu : S = 2 : 1
Hence, the empirical formula for the given compound is
Answer:
The answer would be work with.
Explanation:
Because, if we know what the word interact means then we can look for a word similar to interact. hope this makes sense <3.
