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sladkih [1.3K]
3 years ago
15

For a dilation with a scale factor less than 1, how do the angles and side lengths of the preimage relate to the angles and side

lengths of the image?
A. Angle are proportional;side lengths are larger

B. Angles are proportional;side lengths are smaller

C. Angles are congruent;side lengths are larger

D. Angles are congruent; side lengths are smaller
Mathematics
2 answers:
stiks02 [169]3 years ago
4 0

Answer:

A

Step-by-step explanation:

kakasveta [241]3 years ago
3 0

Answer: option A

Step-by-step explanation:

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Which of the following relations is a function? A. (5, 11), (-9, 2), (-1, 8), (-6, 11) B. (11, 5), (2, -9), (8, -1), (11, -6) C.
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Answer:

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7 0
4 years ago
For f(x)=3x+1 and g(x)=x squared - 6 find (f- g)(x)
saveliy_v [14]
It helps to first clarify that the notation (f - g)(x) simply means f(x) - g(x). Given that, let's look at our f(x) and our g(x) here, and use their definitions to find their difference.

f(x)=3x+1\\g(x)=x^2-6

When we're taking (f - g)(x), we simply substitute the expression 3x + 1 for f(x) and the expression x² - 6 for g(x) to obtain:

(3x+1)-(x^2-6)=3x+1-x^2+6

Or, ordering the polynomial from highest power to lowest and combining the constants:

-x^2+3x+7

Edit: By request, here's what would happen if you had something instead like:

(f\times g)(x)

In this case, you'd have to *multiply* the two function expressions together. Here's what that would look like:

(3x+1)(x^2-6)

Using the distributive property, we can distribute the expression 3x+1 to the terms x^{2} and -6:

(3x+1)x^2-(3x+1)6

Distributing again, we get:

3x(x^2)+x^2-3x(6)+6=3x^3+x^2-18x+6

And we're done.
5 0
3 years ago
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