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Gelneren [198K]
3 years ago
5

Answer please I really need help

Mathematics
2 answers:
iris [78.8K]3 years ago
4 0

Answer:

3125

Step-by-step explanation:

Cuz it is. I 4=5

Ghella [55]3 years ago
4 0

Answer: 3125

Step-by-step explanation:

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Please help me with this.<br> I need a maths genius<br> See pic below.<br> Thanks
adelina 88 [10]

Answer:

a =15

b=70

c=400

d=1500

e=5300

Step-by-step explanation:

it will help u

5 0
3 years ago
What is the square root of s/16 simplified
GREYUIT [131]
It will be 16[tex] 16^{2} = 256
7 0
2 years ago
Read 2 more answers
ABCD is a rectangle that represents a park. The lines show all the paths in the park. The circular path is in the center of the
djyliett [7]

Complete Question:

ABCD Is a rectangle that represents a park.

The lines show all the paths in the park.

The circular path is in the centre of the rectangle and has a diameter of 15m.

Calculate the shortest distance from A to C across the park,using only the lines shown.

*See attachment for the diagram showing the paths in the park.

Answer:

Shortest distance from A to C through the paths only = 102.9 m

Step-by-step explanation:

Length of park = 80 m

Width of park = 50 m

Diameter of the circular path in the center of the park = 15 m

Therefore:

Shortest distance between from A to C across the park if we're to follow only the lines showing the oaths would be = (length of diagonal AC - diameter of the circular path) + (½ of the circumference of the circular path)

✔️Use pythagorean theorem to find AC:

AC = √(80² + 50²) =  √8,900

AC = 94.3398113 ≈ 94.34 m (nearest hundredth)

✔️Diameter of circular path = 15 m

✔️½ of the circumference of the circular path = ½(πd)

d = 15 m

½ of the circumference = ½(π*15) = 23.5619449 ≈ 23.56 m (nearest hundredth)

✔️Shortest distance = (94.34 - 15) + 23.56 = 79.34 + 23.56 = 102.9 m

5 0
3 years ago
You are pulling up an anchor while on a boat. You pull up the anchor at a rate of 0.5 feet per second. After 6 seconds, the anch
LekaFEV [45]

Answer:

the answer is 19 but I feel like it wrong hope it helps

5 0
2 years ago
Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, seve
Lapatulllka [165]

Answer:

a) t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308  

p_v =P(t_{(4)}>2.308) =0.0411

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select \alpha=0.01 we see that p_v >\alpha so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: \mu_2- \mu_1 \leq 0

Alternative hypothesis: \mu_2 -\mu_1 >0

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: 1.2, 1.3, -0.4, 0.8, 0.6

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=0.7

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.678

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308

The next step is calculate the degrees of freedom given by:

df=n-1=5-1=4

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(4)}>2.308) =0.0411

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.  

Part b

The p value is illustrated on the figure attached.

If we select \alpha=0.01 we see that p_v >\alpha so then we have enough evidence to FAIL to reject the null hypothesis.

7 0
2 years ago
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