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loris [4]
3 years ago
6

A) Which of the boxplots, A, B or C, has the largest interquartile range?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

5 10 15 20 25 30 this one is the largest interquartile range

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Me ajuda ai por favor tenho que entregar amanhã
elena-14-01-66 [18.8K]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d){( \frac{1}{3} x - y) }^{2}  =  ({ \frac{1}{9}x }^{2}  -  \frac{2}{3} xy +  {y}^{2} )

e)

(0.25 - a) ^{2}  = (0.25^{2}  - (2)(0.25)a +  {a}^{2} ) \\  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \:  = ( \frac{1}{16}  -  \frac{1}{2} a +  {a}^{2} )

f)

{( \frac{2x}{3}  -  \frac{1}{2} )}^{2}  = ( \frac{4 {x}^{2} }{9}  -  \frac{2x}{3}   +  \frac{1}{4} )

6 0
3 years ago
Thanks, five stars, and brainlilist
nikitadnepr [17]

Answer:

Second option

Step-by-step explanation:

It is given that, if the area of the rectangle to be drawn is 10 square units

To find the length of the rectangle

From the figure, we get the length of AB = 2 units

Therefore Area = length * breadth = 10

Therefore length = 10/2 = 5 units

To find the points of C and D

we have B(-1, 3)

Point C is 5 units below the point B

Therefore C(-1, 3-5) = C(-1,-2)

we have A(1, 3)

The point D is 5 units below the point B

Therefore D(1, 3-5) = A(1,-2)

Therefore the correct answer is option 2.

8 0
3 years ago
Read 2 more answers
What is the exact solution to the system of equations shown on the graph? HELPPPPP !!!​
IgorLugansk [536]

Answer:

The answer is B

Step-by-step explanation:

I made an approximation by looking and using paint 3D to even zoom up the image

pls mark me as brainliest

7 0
3 years ago
Two angles in a triangle measure 33 degrees and 112 degrees. What is the measure of the third angle?
german
35 degrees
Triangles should typically add all up to 180 degrees
3 0
3 years ago
Read 2 more answers
Tank 1 initially contains 50 gals of water with 10 oz of salt in it, while tank 2 initially contains 20 gals of water with 15 oz
Naddik [55]
\dfrac{\mathrm dx_1}{\mathrm dt}=\dfrac{2\text{ oz}}{1\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}
\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_2(t)\text{ oz}}{20\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}

\implies\begin{cases}\dfrac{\mathrm dx_1}{\mathrm dt}=10-\dfrac1{10}x_1\\\\\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac1{10}x_1-\dfrac14x_2\\\\x_1(0)=10\\\\x_2(0)=15\end{cases}
6 0
3 years ago
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