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goblinko [34]
2 years ago
9

In a bag,There are red and blue cubes in the ratio 4:7.I add 10 more red cubes to the bag.Now here are red and blue cubes in the

ratio 6:7.How many blue cubes are in the bag?
Mathematics
1 answer:
Hoochie [10]2 years ago
5 0

Given:

The ratio of red and blue cubes is 4:7.

After adding 10 more red cubes the ratio of red and blue cubes is 6:7.

To find:

The number of blue cubes.

Solution:

The ratio of red and blue cubes is 4:7.

Let the number of red and blue cubes be 4x and 7x respectively.

After adding 10 more red cubes.

Number of red cubes = 4x+10

Then, the ratio of red and blue cubes is 6:7.

\dfrac{4x+10}{7x}=\dfrac{6}{7}

7(4x+10)=6(7x)

28x+70=42x

70=42x-28x

70=14x

Divide both sides by 14.

5=x

Now,

Number of blue cubes in the bag is

7(5)=35

Therefore, the number of blue cubes is 35.

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7 0
1 year ago
Simplify negative 7 and 1 over 8 − negative 9 and 1 over 2
Kryger [21]

Answer:

You can put it into 3 forms:

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4 0
2 years ago
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Help! i will give brainliest!!!
melisa1 [442]
I am assuming the angle is given in degrees.

Answer:

12.71

or in terms of Pi

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Steps:
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L = 2πr(θ/360)
We are given r and θ. Let’s solve for L.

L = 2* π * 8 * (92/360)

The answer is 12.71

or in terms of Pi
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8 0
1 year ago
Match the pairs of equations that represent concentric circles. Tiles
Darina [25.2K]
I will explain you and pair two of the equations as an example to you. Then, you must pair the others.

1) Two circles are concentric if they have the same center and different radii.

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(x - xc)^2 + (y - yc)^2 = r^2.

So, if you have that equation you can inmediately tell the coordinates of the center and the radius of the circle.

3) You can transform the equations given in your picture to the form (x -xc)^2 + (y -yc)^2 = r2 by completing squares.

Example:

Equation: 3x^2 + 3y^2 + 12x - 6y - 21 = 0

rearrange: 3x^2 + 12x + 3y^2 - 6y = 21

extract common factor 3: 3 (x^2 + 4x) + 3(y^2 -2y) = 3*7

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complete squares: (x + 2)^2 - 4 + (y - 1)^2 - 1 = 7

=> (x + 2)^2 + (y - 1)^2 = 12 => center = (-2,1), r = √12.

equation: 4x^2 + 4y^2 + 16x - 8y - 308 = 0

rearrange: 4x^2 + 16x + 4y^2 - 8y = 308

common factor 4: 4 (x^2 + 4x) + 4(y^2 -8y) = 4*77

=> (x^2 + 4x) + (y^2 - 2y) = 77

complete squares: (x + 2)^2  - 4 + (y - 1)^2 - 1 = 77

=> (x + 2)^2 + (y - 1)^2 = 82 => center = (-2,1), r = √82

Therefore, you conclude that these two circumferences have the same center and differet r, so they are concentric.
5 0
3 years ago
what is the solution to the equation fraction 1 over 6x = 2? x = fraction 1 over 12 x = fraction 1 over 3 x = 3 x = 12
hram777 [196]
1/6x = 2.....multiply both sides by the reciprocal 6/1
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6 0
3 years ago
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