Answer:
Step-by-step explanation:
You need to solve the area sector of the bigger circle. Since we now the length of sector is 270, we can set up an equation.
Length of sector DC = 2
r
270 = 2
(8+OA) *(8+OA is the raidus of the bigger circle/sector)*
270/2
= 8 + OA (division)
135/
-8 = OA
135/
-8 = OB (because OA and OB are the raidus of the same circle, so they are congruent)
I hope this helps you! Please correct me if you see a miscalculation <3<3

A water hose had filled up 1⁄3 of a pool after 1⁄2 of an hour. At this rate, how many hours would it take to fill the pool?

It takes 1.5 hours or 1 hour and 30 min. to fill the pool.
Step-by-step explanation:
Answer:
120; 643 units squared
Step-by-step explanation:
Perimeter: Add all the sides, so 120 units
_________________________________
Area: First multiply 19 by 24 for the first shape within this other shape, so That equals 456 units squared. Since we know that one whole side is 36 we can subtract 19 from it to get the lower side of the smaller shape and then multiply that by 11. So the smaller side ends up being 17. So 17 times 11 equals: 187 units squared. Then just add the areas together 187+456=643 units squared.
Answer:
<em>The fraction of the beads that are red is</em>
Step-by-step explanation:
<u>Algebraic Expressions</u>
A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:
r:y = 2:3
y:b = 5:4
We are required to find r:s, where s is the total of beads in the bag, or
s = r + y + b
Thus, we need to calculate:
![\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7Br%2By%2Bb%7D%20%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B1%5D)
Knowing that:
![\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7By%7D%3D%5Cfrac%7B2%7D%7B3%7D%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B2%5D)

Multiplying the equations above:

Simplifying:
![\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Br%7D%7Bb%7D%3D%5Cfrac%7B5%7D%7B6%7D%20%20%20%20%20%20%20%5Cqquad%5Cqquad%20%20%20%20%5B3%5D)
Dividing [1] by r:

Substituting from [2] and [3]:

Operating:



The fraction of the beads that are red is 