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iogann1982 [59]
3 years ago
13

Probabilidad un cubo numérico ​

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

87

Step-by-step explanation:

87

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Dont play with me just answer the question
OleMash [197]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
The table below shows the average yearly balance in a savings account where interest is compounded annually. no money is deposit
djverab [1.8K]
A. Linear with a negative rate of change
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3 years ago
The perimeter of a rectangular field is 100 feet. Which *COULD NOT* be the length and width of the perimeter?
Rina8888 [55]

Answer:

D) L=50 W=50

Step-by-step explanation:

Just "plug and chug" these numbers and see which doesn't work.

A is not it, 20+30=50 (then *2 because we need 4 sides not just 2) 50*2=100

B isn't it, 10+40=50*2=100

C ain't it either 49+1=50*2=100

D is the answer 50+50=100*2=200

7 0
3 years ago
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
3 years ago
The table shows the air temperature in degrees Celsius at different altitudes in kilometers:
miv72 [106K]

Answer:

Third graph, I took the test

Step-by-step explanation:

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3 years ago
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