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2 years ago

Give me some names of a main sequence star other than the sun

Chemistry

2 answers:

ivolga24 [154]2 years ago

7 0

Arietis, camelopardalis, lyncis, scorpii, cancri, canis minoris

VashaNatasha [74]2 years ago

5 0

In astronomy, the main sequence is a continuous and distinctive band of stars that appears on plots of stellar color versus brightness. These color-magnitude plots are known as Hertzsprung–Russell diagrams after their co-developers, Ejnar Hertzsprung and Henry Norris Russell. Stars on this band are known as main-sequence stars or "dwarf" stars.

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Write a balanced equation for the following neutralization reaction HBr+LiOH<->

Sophie [7]

Answer:

HBr(aq) + LiOH(aq) = LiBr(aq) + H2O(l)

Explanation:

For this reaction, the reactants are the hydrobomic acid and the lithium hydroxide which produces the products lithium bromide and water.

8 0

2 years ago

A 111.6 gram sample of iron (MW=55.8) was heated from 0 degrees C to 20 degrees C. It absorbed 1004 Joules of energy. What is th

qwelly [4]

Use the equation q=ncΔT.
q= heat absorbed our released (in this case 1004J)
n= number of moles of sample ( in this case 2.08 mol)
c=molar heat capacity
ΔT=change in temperature (in this case 20°C)
You have to rewrite the equation for c.
c=q/nΔT
c=1004J/(2.08mol x 20°C)
c=24.1 J/mol°C

I hope this helps

7 0

2 years ago

So how is your day my love <br>

Shalnov [3]

Answer:

all good. tell me about your day

5 0

2 years ago

chlorine has 7 outer energy level electrons and argon has 8. what is the difference in the reactivity of these two elements?

Lunna [17]

Chlorine is more reactive than argon, because argon is not reactive at all. Chlorine only has to gain 1 valence electron

6 0

3 years ago

Read 2 more answers

How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

SVEN [57.7K]

<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u /> $3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )$ = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0

2 years ago