“Aluminum” is most likely to
The dichotomous key is not given here, however, the correct dichotomous key is as follows:
step- 1a cell has a nucleus and organelles - go to step 2
1b cell has no nucleus or organelles - bacterial cell
step- 2a cell has a cell wall - go to step 3
2b cell has no cell wall - animal cell
step- 3a cell has chloroplasts - plant cell
3b cell has no chloroplasts - fungal cell
Using this dichotomous key the cell can be identified as - Fungal cell.
A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.
Identification of the given cell:
1. Follow step 1.
- If cells have a nucleus and organelles - yes then go to step 2
2. follow step 2.
- 2a. if cell has a cell wall - yes go to step 3
3. follow step 3.
- 3a. if cell has chloroplasts - no then fungal cell
Fungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.
Thus, Using this dichotomous key the cell can be identified as - Fungal cell.
Learn more about fungal cells:
brainly.com/question/14470940
Answer:
The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.
Explanation:
Consider the ICE take for the solubility of the solid, CuF₂ as:
CuF₂ ⇄ Cu²⁺ + 2F⁻
At t=0 x - -
At t =equilibrium (x-s) s 2s
The expression for Solubility product for CuF₂ is:
![K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5Cleft%20%5B%20Cu%5E%7B2%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20F%5E-%20%5Cright%20%5D%5E2)


Given s = 7.4×10⁻³ M
So, Ksp is:


Ksp = 1.6209×10⁻⁶
Now, we have to calculate the solubility of CuF₂ in NaF.
Thus, NaF already contain 0.20 M F⁻ ions
Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:
CuF₂ ⇄ Cu²⁺ + 2F⁻
At t=0 x - 0.20
At t =equilibrium (x-s') s' 0.20+2s'
The expression for Solubility product for CuF₂ is:
![K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5Cleft%20%5B%20Cu%5E%7B2%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20F%5E-%20%5Cright%20%5D%5E2)

Solving for s', we get
<u>s' = 4.0×10⁻⁵ M</u>
<u>The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.</u>
The number of moles of iron produced can be obtained by the use of stoichiometry.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with mass - mole or mass - volume relationships. Stoichiometric relationships could be used to determine the amount of substance.
Now the reaction equation as well as other details are not shown in this question hence a numerical anwer can not be provided. As such, we can know that the balanced reaction equation can always be used to obtain the amount of iron by stoichiometry.
Learn more about stoichiometry: brainly.com/question/9743981