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3 years ago

A rectangular garden measures 9 feet wide by 12 feet long. If a hose costs $8 per foot, how much would it cost to place a hose

Mathematics

1 answer:

castortr0y [4]3 years ago

5 0

Answer:

120

Step-by-step explanation:

using the pythogorean thereom, we have 12^2+9^2=225

sqrt225=15

15*8=120

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A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centime

mash [69]

Answer: 394 cm3

Step-by-step explanation:

volume of cylinder - volume of 5 balls=extra volume

voc=πr2h=1181.09

pi=22/7

r=3.35

h= 5 x diameter of ball=33.5 (diameter = 2r)

vo5b=5(4/3πr3)=787.4

r=3.35

ev=voc-vo5b

=393.69

ROUND TO 394

5 0

3 years ago

Which shows the list above in order from LEAST to GREATEST<br><br> I’ll mark brainlist : )

irina1246 [14]

The answer is A!

-4.82, -4(2/3) = - 4.667, sqrt 15 is 3.873, 4.15, 465% is 4.65, and 1.5pi =4.65
Hope this helps!

7 0

2 years ago

T-T help me I can't think

BartSMP [9]

Answer:

81 square inches

Step-by-step explanation:

area of a square= s^2

7 0

2 years ago

Hallie made 12 quarts of homemade yogurt. She put the yogurt in 34-cup containers. How many containers did Hallie fill?

GarryVolchara [31]

Answer:

1 container and 14 cups

Step-by-step explanation:

We know that 1 quart = 4 cups

therefore, 12 quart = 48 cups

each container has 34 cups

so one container would be full and remaining 48-34 =14 cups can be filled in another container.

3 0

2 years ago

Brainliest to first correct answer

Artyom0805 [142]

Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2$

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2$

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

5 0

3 years ago