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3 years ago

HELLLPPLPPPP MUDDLE SCHOOLLL!!!!

Mathematics

1 answer:

love history [14]3 years ago

7 0

Answer:

Thats what gauth.math said

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Drag each expression to show whether the product is less than 1, equal to 1, or greater than 1.

laila [671]

Answer:

967354176/8725762864 because it can be a common denomonater

Step-by-step explanation:

7 0

3 years ago

Find the area of the figure. A = Is it m, m2, or m3

enot [183]

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

5 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

Helppppppppppppppppppppppppp

Maslowich

Answer:

I can't seem to solve these but hope this information helps :)

Step-by-step explanation:

Remove any grouping symbol such as brackets and parentheses by multiplying factors.

Use the exponent rule to remove grouping if the terms are containing exponents.

Combine the like terms by addition or subtraction.

Combine the constants.

7 0

3 years ago

Read 2 more answers

Plz help!

GuDViN [60]

Answer:

5x - y = 27

Step-by-step explanation:

Slope is the direction of line and it is calculated as,

$Slope = \frac{y-y_{1}}{x-x_{1}}
$

where (x₁, y₁) is any two points on the line.

Here, we have given that

Slope = 5 and (x₁, y₁) = (5, -2)

∴ $5 = \frac{y-(-2)}{x-5}
$

⇒ 5(x - 5) = y + 2

⇒ 5x - 25 = y + 2

⇒ 5x - y = 27

Hence, the equation of a line is: 5x - y = 27

5 0

3 years ago