True or false: This balanced equation shows the combustion of ethane: 2C2H6 + 7O2 → 4CO2 + 6H2O
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<h3>Answer:</h3>
Gas law : Boyle's law
New pressure: 66.24 atm
<h3>Explanation:</h3>Concept tested: Gas laws (Boyle's law)
<u>We are given,</u>
- Initial pressure, P₁ = 2.86 atm
- Initial volume, V₁ = 8472 mL
- New volume, V₂ IS 365.8 mL
We need to determine the new pressure, P₂
- According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.
- That is,
- This means , PV = k (constant)
- Therefore; P₁V₁ = P₂V₂
- Rearranging the formula, we can get the new pressure, P₂
P₂ = P₁V₁ ÷ V₂
= (2.86 atm × 8472 mL) ÷ 365.8 mL
= 66.24 atm
Therefore, the new pressure is 66.24 atm
Aldehydes and ketones having α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH).
The initial product formed during this reaction is β-hydroxy alcohol, which then undergoes dehydration to form α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one.
The complete reaction product formed is shown below.
The initial product formed during this reaction is β-hydroxy alcohol, which then undergoes dehydration to form α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one.
The complete reaction product formed is shown below.