The cations and anions can be identified using cataloged reactions schemes. For instance, the copper II ion can be identified by reaction with sodium hydroxide.
The sodium cation is easily identified by flame test. sodium imparts a yellow color to a flame. The chloride ion is identified by the use of a mixture of HNO3/AgNO3 solution. The color of the precipitate shows which halide ion is present. A white precipitate indicates the presence of the chloride ion.
The potassium cation is also identified by flame test. The ion imparts a lilac color to flame. Addition of acidified FeSO4 solution is used to confirm the presence of the nitrate ion. Formation of a brown ring is a positive test for the nitrate ion.
For CuSO4, the presence of copper II ion can be confirmed using dilute NaOH. If a light blue precipitate is formed which dissolves in excess NaOH then the copper II ion is confirmed. The presence of the sulfate ion is confirmed using a solution of barium nitrate and dilute nitric acid. Formation of a white precipitate is a positive test for the sulfate ion.
Learn more: brainly.com/question/5624100
greenhouse gases can cause Earth's atmosphere to trap more and more heat. This causes Earth to warm up.
Answer:
You need to add 400mL of water
Explanation:
500mL = 5 M HCI That means that if you divide both sides by 5
100mL = 1 M HCI If you need ot get rid of 4 M HCI then you add 400 mL of water because that is what it is equal to
Since you have not included the chemical reaction I will explain you in detail.
1) To determine the limiting agent you need two things:
- the balanced chemical equation
- the amount of every reactant involved as per the chemical equation
2) The work is:
- state the mole ratios of all the reactants: these are the ratios of the coefficientes of the reactans in the balanced chemical equation.
- determine the number of moles of each reactant with this formula:
number of moles = (mass in grams) / (molar mass)
- set the proportion with the two ratios (theoretical moles and actual moles)
- compare which reactant is below than the stated by the theoretical ratio.
3) Example: determine the limiting agent in this reaction if there are 100 grams of each reactant:
i) Chemical equation: H₂ + O₂ → H₂O
ii) Balanced chemical equation: 2H₂ + O₂ → 2H₂O
iii) Theoretical mole ration of the reactants: 2 moles H₂ : 1 mol O₂
iv) Covert 100 g of H₂ into number of moles
n = 100g / 2g/mol = 50 mol of H₂
v) Convert 100 g of O₂ to moles:
n = 100 g / 32 g/mol = 3.125 mol
vi) Actual ratio: 50 mol H₂ / 3.125 mol O₂
vii) Compare the two ratios:
2 mol H₂ / 1 mol O ₂ < 50 mol H₂ / 3.125 mol O₂
Conclusion: the actual ratio of H₂ to O₂ is greater than the theoretical ratio, meaning that the H₂ is in excess respect to the O₂. And that means that O₂ will be consumed completely while some H₂ will remain without react.
Therefore, the O₂ is the limiting reactant in this example.
