So using a calculator this question is really easy 125,000x 1.35 ^10 =.
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A three-letter word used to show division in a word problem is PER.
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
Answer:
-4
Step-by-step explanation:
Low tide is 1 ft below average water level.
High tide is 5 ft higher than low tide.
High tide is 5 ft higher than low tide. Start at low tide. Use 1 ft of the 5 ft to go up to average water level. You still have 4 ft more to go to high tide. That means high tide is 4 ft above average water level. Then, the average water level is 4 ft below high tide. A height below another height is is a negative number of feet from that height. Since the average water height is 4 ft BELOW high tide, then relative to high tide, the average water level is -4 ft.
Answer: -4
X=5 because you plug in the y into the equation y-x=17
