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Sauron [17]
3 years ago
10

HELP ME WITH THIS PLEASE ITS DUE IN 4 MINUTES

Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

i guessing its due now srry i was too late

Step-by-step explanation:

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Tim has $20 to buy snacks for 12 people in an office. Each person will get one snack. Tim is buying bags of pretzels that cost $
Greeley [361]

Answer:

  8 bags of pretzels

Step-by-step explanation:

Let x represent the number of bags of pretzels Tim buys. We assume he spends exactly $20 on exactly 12 bags of snack food. Then his purchase is ...

  1.50x + 2.00(12-x) = 20.00

  -0.50x +24.00 = 20.00 . . . eliminate parentheses, collect terms

  -0.50x = -4.00 . . . . . . . . . . .subtract 24

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Tim will buy 8 bags of pretzels.

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3 years ago
Is 6/7 equal to 3/4?
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Ok so, when working to find if a fraction is equal to another you must know what it is cut down by. So 6 / 2 = 3. Now let's break down 7 by 2. It is 3.5 that is not four. So no 6/7 so not equal to 3/4. 
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3 years ago
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dusya [7]
Equation of a line:
y=mx+c

m = gradient: The difference between two y points and two x points.
m= \frac{\Delta y}{\Delta x}

c = y-intercept: Where the line crosses the y-axis (x=0)

You have:
y=\textunderscore\textunderscore \ x + \textunderscore
so you are missing the m and the c.

To calculate m find two y coordinates -you have (12, <u>7</u>) and (0, <u>1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>12</u>, 7) and (<u>0</u>, 1)- This gives:

m= \frac{7-1}{12-0}
m= \frac{6}{12}
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To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:

c=1

When you plug these values into the equation you get your answer:

y=0.5x+1
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3 years ago
Plzz help!!! Will give Brainiest
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The three acute angles are 70 and the obtuse ones are 110.
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How many ways can 4 people sit in a row of 7 ​chairs?
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7\cdot6\cdot5\cdot4=840

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3 years ago
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