Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
The correct answer will be- epimysium
Explanation:
Epimysium is the fibrous connective tissue envelope which surrounds the muscle fibers of the muscle as a whole.
The epimysium plays an important role in maintaining the muscle structure as it protects the muscle from the friction caused by the associated bones and the muscles.
The epimysium is continuous with other layers called the endomysium, perimysium, tendons and the fascia.
Thus, epimysium is the correct answers.
Before the food handler handles any type of food or cooks and prepares them. It is best that they should properly wash their hands in order to prepare them with clean hands. It is best to wash the hands before handling the food so that the hand that could have exposed to dirt could be cleaned and it will prevent the food from being contaminated.
B is correct
D is appealing but the electrons spend more time around the oxygen than the hydrogen
