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s344n2d4d5 [400]
3 years ago
7

What is 5/2x + 2y = 5

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

y= -x+1/2

Step-by-step explanation:

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The 2nd problem. pls i need to know the answer
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Kianna had 480 and she shared 1/8.....1/8 * 480 = 480/8 = 60
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together, they shared (70 + 60) = 130
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3 years ago
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A candy box company places an average of 20 truffles in a one pound box. The number of truffles per box never varies from the av
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(x-20) 2
that is the answer

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3 years ago
What is the derivative of y=tan(arcsin(x))?
Anuta_ua [19.1K]
Hello,

(tg(x))'=1/cos²(x)

(arcsin(x))'=1/√(1-x²)

cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²


(tg(arcsin(x)))'= \dfrac{1}{cos(arcsin(x)))^2} * \dfrac{1}{\sqrt{1-x^2}} \\

=\dfrac{1}{1-sin(arcsin(x))^2}* \dfrac{1}{\sqrt{1-x^2}} \\

= \dfrac{1}{1-x^2} * \dfrac{1}{\sqrt{1-x^2}} \\

\boxed{= \dfrac{\sqrt{1-x^2}}{x^4-2x^2+1}}\\


4 0
3 years ago
Han is cycling at a speed of -8 miles per hour; if he starts at the same zero point, what will his position be after 45 minutes?
baherus [9]

Answer:

-6mph

Step-by-step explanation:

45 is 3/4hour so -8 times 3/4= -24/4=-6mph

7 0
3 years ago
Average rate of change help!!
frez [133]

Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

We need to determine the average rate of change over the interval 0 \leq x \leq 5

<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

3 0
3 years ago
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