<em>when </em><em>South </em><em>and </em><em>North </em><em>poles </em><em>are </em><em>placed </em><em>together </em><em>they </em><em>attract </em><em>as </em><em>they </em><em>are </em><em>opposite</em><em> </em><em>poles. </em><em>In</em><em> </em><em>magnets </em><em>opposite </em><em>po</em><em>l</em><em>es </em><em>are </em><em>attracted </em><em>and </em><em>like </em><em>poles </em><em>are </em><em>repelled. </em>
Answer:
All nuclear power plants use nuclear fission, and most nuclear power plants use uranium atoms. During nuclear fission, a neutron collides with a uranium atom and splits it, releasing a large amount of energy in the form of heat and radiation. More neutrons are also released when a uranium atom splits.
<span>A compound machine is a combination of two or more "Machines"
Hope this helps!</span><span />
Answer:
α = π/3
β = π/6
Explanation:
Use arc length equation to find the sum of the angles.
s = rθ
π/20 m = (0.1 m) (α + β)
π/2 = α + β
Draw a free body diagram for each sphere. Both spheres have three forces acting on them:
Weight force mg pulling down,
Normal force N pushing perpendicular to the surface,
and tension force T pulling tangential to the surface.
Sum of forces on A in the tangential direction:
∑F = ma
T − m₁g sin α = 0
T = m₁g sin α
Sum of forces on B in the tangential direction:
∑F = ma
T − m₂g sin β = 0
T = m₂g sin β
Substituting:
m₁g sin α = m₂g sin β
m₁ sin α = m₂ sin β
(1 kg) sin α = (√3 kg) sin (π/2 − α)
1 sin α = √3 cos α
tan α = √3
α = π/3
β = π/6
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