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Elena-2011 [213]
3 years ago
10

How would I solve this? 6 = a/4 + 2

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

Answer: a equals 16

Step-by-step explanation: so you need it to to equal 6 so 4x4 makes 16 so 16/4 makes 4 plus 2 makes 6

kotegsom [21]3 years ago
4 0

Answer:

a = 16

Step-by-step explanation:

first, get rid/ cancled out the number by a so it can stand alone.

6 = a/4 + 2

-2               -2   (since it is positive we have to subtract it)

then, we multiply 4 on both sides, so the 4 gets canclled out.

4 x 4 = a/4 x 4

16 = a

now we check by replacing a in the equation with 16.

6 = 16/4 + 2

6 =  4 + 2

 6 = 6    . that means it is correct.

 

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Answer:

Here's what I get.

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9. (6, -8)

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\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

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∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

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\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

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explanation-
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