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2 years ago

ITS ALMOST MY BIRTHDAY GUYSSSSSSS! 35 days 14 hours 13 minutes 30 seconds

Mathematics

2 answers:

scZoUnD [109]2 years ago

8 0

Answer:Wow great calculations

You're almost there.

Step-by-step explanation:

Damm [24]2 years ago

3 0

Answer:

happy early BDAY

Step-by-step explanation:

You might be interested in

The area of a rectangle is 229.2 m2. If the length is 15 m, what is the perimeter of the rectangle

igor_vitrenko [27]

Answer:

$\large\boxed{P=60.56\ m}$

Step-by-step explanation:

The formula of an area of a rectangle:

$A=lw$

l - length

w - width

We have

$A=229.2\ m^2\\\l=15\ m$

Substitute:

$15w=229.2$ <em>divide both sides by 15</em>

$w=15.28\ m$

The formula of a perimeter of a rectangle:

$P=2(l+w)$

Substitute:

$P=2(15+15.28)=2(30.28)=60.56\ m$

8 0

3 years ago

Please tel me what goes where

maria [59]

Step-by-step explanation:

A- Equilateral (all of the angles are the same)

B- isosceles (just two angles are the same)

C- scalene (non of the angles are the same)

7 0

2 years ago

Read 2 more answers

Help me deadline today

weeeeeb [17]

Answer:

Step-by-step explanation:

The equation becomes 9 *4 * 1/6. Then you simplify and get 6.

Please mark me as Brainliest if it is correct, thx.

8 0

1 year ago

The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%

liq [111]

<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by $\frac{100+1.8}{100}$ = $\frac{101.8}{100}$ .

So, the population in the year t can be given by $P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}$

Population in the year 2000 = $3,381,000\textrm{x}(\frac{101.8}{100})^{6}$ = $3,762,979.38$

Population in year 2000 = 3,762,979

Let us assume population doubles by year $y$ .

$2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}$

$log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})$

$y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537$

$y$ ≈ $2033$

∴ By 2033, the population doubles.

4 0

3 years ago

The local newspaper has letters to the editor from 10 people. If this number represents 2% of all of the newspaper's readers,

RideAnS [48]

Answer:

The newspaper has 500 readers.

Step-by-step explanation:

We have that:

10 people is 2$ of all newspapers readers, which total t. This means that:

$0.02t = 10$

$t = \frac{10}{0.02}$

$t = \frac{1000}{2}$

$t = 500$

The newspaper has 500 readers.

5 0

2 years ago