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nirvana33 [79]
3 years ago
9

Based on Gay-Lussac's law, which of the following statements is true for an ideal gas at constant volume and mole amount? (4 poi

nts)
a
Pressure is directly proportional to the absolute temperature.

b
Pressure is inversely proportional to the absolute temperature.

c
The number of collisions decreases with increase in pressure.

d
The number of collisions is independent of pressure.
Chemistry
1 answer:
Andreas93 [3]3 years ago
5 0
Is Gay-Lussac really gay?
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Determine the molecular formula of a compound having the empirical formula C9H17O and a molar mass of 847.56g/mol.
Arlecino [84]
 The  molecular  formula of a compound  having  the empirical  formula  C9H17O  is calculated as below

(C9H17O)n =847.56

{(12 x9 + 1 x17 + 1 x16)}n= 847.56

147 n = 847.56
divide bot
h side by 147
n= 6

(C9H17O)6 therefore the molecular formula = C54H102O6
7 0
4 years ago
How many atoms does the formula 2HgO have?
yKpoI14uk [10]

Answer:

4

Explanation:

2HgO

2 * 1 Hg atom = 2 Hg atoms

2 * 1 O atom = 2 O atoms

2+2 = 4 atoms total

3 0
3 years ago
If 980kJ of energy as heat are transferred to 6.2L of water at 291 K what will the final temperature be? The specific heat of wa
In-s [12.5K]

Answer:

Final temperature = T₂ = 328.815 K

Explanation:

Given data:

Given energy = 980 KJ = 980×1000= 980000 J

Volume = 6.2 L

Initial temperature =T₁= 291 K

Specific heat of water = 4.18 j /g .K

Final temperature = T₂ = ?

Formula:

Q = m. c . ΔT

ΔT = T₂ - T₁

we will first convert the litter into milliliter

6.2 × 1000 = 6200 mL

It is given in question that

1 mL = 1 g

6200 mL = 6200 g

Now we will put the values in formula,

Q = m. c . (T₂ - T₁)

980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)

980000 j = 25916 j/ k .  (T₂ - 291 K)

980000 j /  25916 j/ k =  T₂ - 291 K

37.8145 K + 291 K =T₂

T₂ = 328.815 K

4 0
4 years ago
Which of the following statements is TRUE?
Karo-lina-s [1.5K]

Answer:

The correct option is E.

Explanation:

Average speed of the gas molecules = v_a

v_a=\sqrt{\frac{2RT}{M}}

T = Temperature of the gas molecule

M = molar mass of gas molecule

R = gas constant

v_a\propto \frac{1}{M}

Higher the molar mass of the molecule lesser will be the speed and vice versa.

Hence, statement A is not true.

Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Larger the molar mass that larger the molecule lessor will be the effusion and vice versa.

Hence, statement B is not true.

According to Boyle's law, pressure of the gas is inversely proportional o the volume occupied by the gas at constant temperature. And same can also be observed from ideal gas law:

PV=nRT

P=\frac{nRT}{V}

P\propto \frac{1}{V}

Higher the pressure of the gas lower will be the volume occupied by the gas and vice versa.

Hence, statement C is not true.

With rise in temperature, effusion of gas molecule increase as kinetic energy of gas molecules increases in with increase in temperature.

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

K=\frac{3RT}{2N_A}

where,

K = Average kinetic energy

R = Gas constant

T = Temperature of the system

N_A = Avogadro's number

K\propto T

Higher the temperature more will be kinetic energy of gas molecule more easily it will effuse.

Hence, statement D is not true.

From this we can conclude that out of five statements first 4 statements are not true which means that none of these statements are true.

3 0
4 years ago
What is true about the combustion of water?
miv72 [106K]

Answer:

C

Explanation:

Spontaneous combustion is a type of combustion which occurs by self-heating (increase in temperature due to exothermic internal reactions), followed by thermal runaway (self-heating which rapidly accelerates to high temperatures) and finally, ignition.

7 0
3 years ago
Read 2 more answers
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