V ( H2SO4) = 35 mL / 1000 => 0.035 L
M ( H2SO4) = ?
V ( NaOH ) = 25 mL / 1000 => 0.025 L
M ( NaOH ) = 0.320 M
number of moles NaOH:
n = M x V
n = 0.025 x 0.320 => 0.008 moles of NaOH
Mole ratio:
<span>2 NaOH + H2SO4 = Na2SO4 + 2 H2O
</span>
2 moles NaOH ---------------------- 1 mole H2SO4
0.008 moles moles NaOH ---------- ??
0.008 x 1 / 2 => 0.004 moles of H2SO4 :
Therefore:
M ( H2SO4) = n / V
M = 0.004 / 0.035
= 0.114 M
hope this helps!
Answer:
Please find the complete solution in the attached file.
Explanation:
Left side metals right side non metals. arrganged in groups (columns) and periods (rows), each group tells you amount of valence electrons
Answer:
about 30g
Explanation:
Molarity = mol/L
*convert mL to L*
3M=xmol/.25
xmol = .75
*convert to g
.75 mol NaOH * 40g/mol = 30 g
