All categories

2 years ago

Who had the idea to study humans as groups rather than as individuals?

Chemistry

2 answers:

Ratling [72]2 years ago

7 0

The answer is Malthus, A

Vedmedyk [2.9K]2 years ago

6 0

V. C. Wynne-Edwards and Konrad Lorenz were the first authors to raise the concept of altruism. This was later reiterated by David Sloan Wilson, E. O. Wilson and Elliott Sober in 1994 whose works referred to social organisms such as ants.

You might be interested in

During active transport, substances move from regions of blank concentration to regions of blank concentration

Annette [7]

Active transport runs counter to facilitated diffusion. In active transport, molecules move against the concentration gradients, running from areas of lower concentration to areas of higher concentration. This is where energy is used.

4 0

2 years ago

Chlorine gas was bubbled in a solution of sodium bromide. Explain what was observed.

saveliy_v [14]

A displacement reaction will occur from the system given above. The chlorine molecules will displace the bromide ions in the solution of sodium bromide. The reaction will yield to sodium chloride and bromine. The reaction will be:

2NaBr + Cl2 = 2NaCl + Br2

5 0

2 years ago

Read 2 more answers

The answer to question 2

Bad White [126]

Answer:

Explanation:

You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.

$M_{r}$ : 258.21 18.02

KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O

Mass/g: 4.74 2.16

Step 1. Calculate the mass of the KAl(SO₄)₂.

Mass = 4.74 g – 2.16 g = 2.58 g.

Step 2. Calculate the moles of each product.

$\text{Moles of KAl(SO}_{4})_{2} = \text{2.58 g} \times \frac{\text{1 mol} }{\text{258.21 g}} = 9.992 \times 10^{-3} \text{ mol}$

$\text{Moles of H}_{2}\text{O} = \text{2.16 g} \times \frac{\text{1 mol} }{\text{18.02 g}} = \text{ 0.1200 mol}$

Step 3. Calculate the molar ratio of the two products.

$\frac{\text{Moles of KAl(SO}_{4})_{2}}{\text{Moles of H}_{2}\text{O}} = \frac{ 9.992 \times 10^{-3} \text{ mol}}{\text{ 0.1200 mol} } = \frac{1 }{12.01} \approx \frac{ 1}{ 12}$

1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.

3 0

2 years ago

Please help i'm not good at this 3, (i'll give brainliest to the most helpful answer)

stira [4]

epicene Anika Hunger Games a Hunger Games Hunger Games Hunger Games Hunger Games for no Mommy get on with the quizzy gay gay gay

7 0

2 years ago

Your veterinarian is administering a sedative to your 50 pound dog. The sedative is mixed in saline solution. Unfortunately the

Olin [163]

Answer:

26.25 mL

Explanation:

This is a dilution problem. First, let us calculate the volume of final solution needed:

The dog weighs 50 pounds and the sedative is administered at 0/7 ml per pound. Hence:

50 x 0.7 = 35 mL

A total volume of 35 mL, 2.5% solution of the sedative will be needed.

But 10% solution is available. There needs to be a dilution with saline water, but what volume of the 10% solution would be diluted?

initial volume = ?

final volume = 35 mL

initial concentration = 10%

final concentration = 2.5%

Using dilution equation:

initial concentration x initial volume = final concentration x final volume

initial volume = $\frac{final concentration*final volume}{initial concentration}$

= 2.5 x 35/10 = 8.75 mL

Hence, 8.75 mL of the 10% pre-mixed sedative will be required.

But 35 mL is needed? The 8.75 mL is marked up to 35 mL with saline water.

35 - 8.75 = 26.25 mL

Therefore, 26.25 mL of saline water will be added to 8.75 mL of the 10% pre-mixed sedative to give 2.5%, 35 mL needed for the dog.

5 0

2 years ago