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Trava [24]
3 years ago
5

Who had the idea to study humans as groups rather than as individuals?

Chemistry
2 answers:
Ratling [72]3 years ago
7 0

The answer is Malthus, A

Vedmedyk [2.9K]3 years ago
6 0
<span><span>V. C. Wynne-Edwards and Konrad Lorenz were the first authors to raise the concept of altruism</span><span>. This was later reiterated by  </span>David Sloan Wilson, E. O. Wilson and Elliott Sober<span> in 1994 whose works referred to social organisms such as ants</span></span>.




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An oxide of nitrogen contains 30.45 mass % N.
N76 [4]

An oxide of nitrogen contains 30.45 mass % N, if the molar mass is 90± 5 g/mol the molecular formula is N₂O₄.

<h3>What is molar mass?</h3>

The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. A substance's molar mass is one of its properties. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.

<h3>How to find the molecular formula?</h3>

The whole-number multiple is defined as follows.

Whole-number multiple = \frac{molar mass (g/mol)}{empirical formula mass (g/mol)}

The empirical formula mass is shown below.

Mw of empirical formula = Mw of N+ 2 x (Mw of O)

                                      = 14.01 g/mol + 2 x (16.00 g/mol)

                                      = 46.01 g/mol

With the given molar mass or the molecular formula mass, we can get the whole-number multiple for the compound.

Whole-number multiple = \frac{90 g/mol }{46.01 g/mol} ≈ 2

Multiplying the subscripts of NO2 by 2, the molecular formula is N(1x2)O(2x2)= N2O4.

To learn more about molar mass visit:

brainly.com/question/12127540

#SPJ4

5 0
2 years ago
How many moles of calcium (Ca) atoms are there in 77.4 g of Ca?
Vinvika [58]
Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
8 0
3 years ago
Read 2 more answers
Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0
3 years ago
Why are you so much older on Mercury?
Alinara [238K]

Answer:As you can see from the very different numbers in the boxes above, your age changes (sometimes quite a lot) ... Mercury is the closest planet to the Sun and so has a smaller orbit path – it takes just 88 Earth days

Explanation:

4 0
3 years ago
Read 2 more answers
What are you suppose to do for number 8?
Nadya [2.5K]

Answer:

See the images below  

Step-by-step explanation:

To draw a dot diagram of an atom, you locate the element in the Periodic Table and figure out how many valence electrons it has. Then you distribute the electrons as dots around the atom,

a. Silicon.

Si is in Group 14, so it has four valence electrons.

b. Xenon

Xenon is in Group 18, so it has eight valence electrons. We group them as four pairs around the xenon atom.

c. Calcium

Calcium is in Group 2, so it has two valence electrons. They are in a single subshell, so we write them as a pair on the calcium atom.

d. Water

Oxygen is in Group 16, so it has six valence electrons. The hydrogen atoms each contribute one electron, so there are eight valence electrons.

Chemists often use a dash to represent a pair of electrons in a bond.

3 0
3 years ago
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