Atoms of elements that are in the same group have the same number of

You are Investigating an organic compound. It has the following characteristics: an oxygen atom Is bonded to two carbon groups,

Vesna [10]

The correct answer most likely be c

7 0

4 years ago

Sir J.J. Thompson discovered the electron in 1897. How did Thompson explain the overall neutral charge of the atom?

navik [9.2K]

your answer is C you're welcome

4 0

4 years ago

A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce

Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS $_{sublimation}$ = $S_{vapor}$ - S $_{solid}$ = $\frac{\Delta H_{sublimation}}{T}$

Where:

ΔH $_{sublimation}$ = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime = 26.1 KJ/mol × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS $_{sublimation}$ = $\frac{230.695 KJ}{194.65 K}$

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS $_{universe}$ = $\Delta S_{system}$ + ΔS $_{surrounding}$

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS $_{universe}$ = $\frac{Q}{ T_{system}}$ $-\frac{Q}{T_{surrounding}}$

=1.185 KJ/K - $-\frac{230.695 KJ}{285.15K}$ = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0

3 years ago

In this lab, you will observe the properties of oil, cornstarch, salt, and sodium bicarbonate. You will use the properties to cl

snow_tiger [21]

An ionic compound is a chemical compound dissociated into positive and negative ions, but globally neutral (it is a bond that usually involves a metal).

A covalent bond is a bond in which two valence electrons are shared between two non-metals (which is often the case in organic substances). In this type of bond, there must be an electronegativity difference of less than 1.7 on the Pauling scale.

Returning to the question, the first question to investigate is if the substance is simple or compound (all of them are compound).

The next question for the substances is if there's a metallic atom or a carbon atom in the substance.

The next investigation is a confirmation, by calculating the electronegativity difference between the atoms in the substances according to Pauli's scale. If it's under 1.7, it's a covalent bond, so a covalent compound. if not it's an ionic bond, so an ionic compound.

4 0

3 years ago

Read 2 more answers

what is the trend for the size as you go from Be to Mg to Ca? does the atomic size increase, decrease, or remain the same? how w

lys-0071 [83]

Answer:

the size of Ca is the greatest ,then Mg is the greater on size than Be

Explanation:

if you make the electron configuration for each of the elements, what is the main difference u gonna see ?

Be 4 1s2/2s2

Mg 12 1s2 /2s2 2p6/3s2

Ca 20 1s2 /2s2 2p6/3s2 3p6 3d/4s2

see that all the elements are in the same group but are in different period

u gonna see the last electron valance shell in Ca are too far from its nucleus but in Be the last electrons are too close and more attracted to the atom's nucleus , so the size of Ca is the biggest then Mg then Be

4 0

4 years ago