Intersecting on the y axis means x=0.
Plug x=0 in the equation to find out the y value of the intercept> 0+4y-24=0, y=6
so the both line passes the point (0,6)
two perpendicular lines have slopes that are negative reciprocals of each other, that is, if one slope is a/b, the other is -b/a
In this case, the line x+4y-24=0, 4y=-x+24, y=-1/4 x + 6, the slope is -1/4, so the slope of the perpendicular line is 4/1.
the equation is y=4x+6
78 is the answer
If you substract 914-836 that equals 78
And if you substract 836-758=78 too
Answer:
-2x³ - 14x² + 7x - 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(3x³ - 2x² + 4x - 8) - (5x³ + 12x² - 3x - 4)
<u>Step 2: Simplify</u>
- [Distributive Property] Distribute negative: 3x³ - 2x² + 4x - 8 - 5x³ - 12x² + 3x + 4
- Combine like terms (x³): -2x³ - 2x² + 4x - 8 - 12x² + 3x + 4
- Combine like terms (x²): -2x³ - 14x² + 4x - 8 + 3x + 4
- Combine like terms (x): -2x³ - 14x² + 7x - 8 + 4
- Combine like terms: -2x³ - 14x² + 7x - 4
Answer:
(2)
Step-by-step explanation:
-3,2
-1,-1
![y = ax + b \\ 2 = - 3a + b \\ - 1 = - a + b \\ 3 = - 2a \\ a = - 1.5](https://tex.z-dn.net/?f=y%20%3D%20ax%20%2B%20b%20%5C%5C%202%20%3D%20%20-%203a%20%2B%20b%20%5C%5C%20%20-%201%20%3D%20%20-%20a%20%2B%20b%20%5C%5C%203%20%3D%20%20-%202a%20%5C%5C%20a%20%3D%20%20-%201.5)
slope is -1.5
You have to find the difference in height between both checkpoints. To do this just calculate 196 - 52. Checkpoint 5 is 144 (meters?) higher than Checkpoint 2.