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postnew [5]
2 years ago
14

A car accelerates from rest at 2 m/s. what is the speed after 8 sec?

Physics
1 answer:
beks73 [17]2 years ago
6 0

Answer:

16m/s

Explanation:

v_{f}=v_{i}+at

v_{f}=0+2\cdot8

v_{f}=16\ \frac{m}{s}

Therefore,  the speed after 8 seconds is 16m/s

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What is the mass of a truck in grams of it produces a force of 1500N while accelerating at a rate of 6 m/s²?​
aleksley [76]

Answer:

250,000

Explanation:

<h2> </h2>

<h2>formula = ( F=ma </h2>

  • F=1500N
  • a=6m/s^2
  • F= ma
  • m=?
  • 1500/6 = m
  • m=250 kg
  • 1kg =1000gm so 250kg =250,000gm
  • m =250×10^3 gm
5 0
3 years ago
What are the dates of the atlantic hurricane season
Bad White [126]

Answer:

Starts on Saturday, June 1

and ends on

Saturday, November 30

Explanation:

6 0
3 years ago
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How are balanced &amp; unbalanced forces related to net force?
Levart [38]

Answer:

An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. ... A net force = unbalanced force. If however, the forces are balanced (in equilibrium) and there is no net force, the object will not accelerate and the velocity will remain constant.

Explanation:

4 0
3 years ago
A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters
JulijaS [17]

Answer:

100/10 = 10 , 10 × 10 = 100÷20 = 5

I'm pretty sure its wrong

8 0
3 years ago
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Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a
skelet666 [1.2K]

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

<u>W = 1418.9 J = 1.418 KJ</u>

6 0
3 years ago
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