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Vaselesa [24]
3 years ago
14

Which has the greatest frictional force among this surfaces

Physics
1 answer:
fomenos3 years ago
7 0

Answer:

D.sandy floor

Explanation:

hope this help you

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The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you
katrin2010 [14]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The spring scale F_2 reads  F_2 =  2.4225 \ N

Explanation:

From the question we are told that

      The first force is  F_1  =  10.5 \ N

      The acceleration by which the cart moves to the right is  a = 2.50  \ m/s^2

      The mass of the cart is  m  = 3.231  kg

       

Generally the net force on the cart is  

       F_{net} = F_1 -  F_2

This net force is mathematically represented as

      F_{net} =  m * a

So  

        m*  a =  10 - F_2

        F_2 =  10.5 -  2.5 (3.231)

        F_2 =  2.4225 \ N

 

3 0
3 years ago
If an object has a large momentum, how easy is it to stop, and why?
podryga [215]
It is dificult to stop an object with a lot of momentum becuase of inertia with means that a moving object will want to keep moving and a stationary object wil want to stay stationary and the larger the momentum of the moving object the harder it will be to stop
7 0
3 years ago
Why is the unit of momentum called derived unit​
Mnenie [13.5K]

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

kinetic energy = 1/2 mv2

E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

8 0
3 years ago
A car wheel turns through 277° in 10.7 s. Calculate the angular speed of the wheel.
slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

Explanation:

The angle through which the car wheel turns, Δθ = 277° = 277/360 × 2·π radian

The time it takes for the car wheel to turn, Δt = 10.7 s

The angular speed, ω is given by the following equation;

Angular \ speed = \dfrac{Change \ in \ angular \ rotation }{Change \ in \ time} = \dfrac{\Delta \theta}{\Delta t}

Substituting the known values for Δθ and Δt gives;

Angular \ speed = \dfrac{\dfrac{277 ^{\circ}}{360 ^{\circ }  }  \times 2 \times \pi \ radian}{10.7 \ seconds} \approx 0.452 \ rad/s

The angular speed of the wheel = 0.452 rad/s

3 0
3 years ago
A mass of 0.30kg is attached to a spring and is set into motion with a period of 0.24s. what is the spring constant of the sprin
Alenkinab [10]

Answer:

The spring constant of the spring is 205.42 N/m.

Explanation:

Springs have their own natural "spring constants" that define how stiff they are. The letter k is used for the spring constant, and it has the units N/m.

                                                         k = -F/x

The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.

Given:

mass of object in SHM = m = 0.30 kg

Time period of the spring mass system = 0.24s

Spring constant = k ?

Finding 'k' using Time period 'T':

We know that  

6 0
3 years ago
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