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2 years ago

A snowmobile has an initial velocity of 3.0 m/s

2 answers:

7 0

My answer to the problem is as follows:

<span>1. Use the kinematic formula

Vf = Vi + a*t

for a, Vi = 3.0 m/s, a = 0.5 m/s/s, and t = 7.o s.

for b, Vf = 0, Vi = 3.0 m/s, and a = -0.60 m/s/s.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>

bazaltina [42]2 years ago

3 0

Answer:

Part a)

$v_f = 6.5 m/s$

Part b)

$t = 5 seconds$

Explanation:

Part a)

As we know that

$v_f = v_i + at$

here we know that

$v_i = 3 m/s$

$a = 0.5 m/s^2$

$t = 7.0 s$

so we will have

$v_f = 3 + (0.5)(7.0)$

$v_f = 6.5 m/s$

Part b)

if finally the snowmobile comes to rest

So here we can say that

$v_f = 0$

$v_i = 3.0 m/s$

$a = -0.60 m/s^2$

so now we have

$v_f = v_i + at$

$0 = 3.0 - (0.60)t$

$t = 5 s$

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Two identical satellites orbit the earth in stable orbits. One satellite orbits with a speed v at a distance r from the center o

jolli1 [7]

Answer:

c)At a distance greater than r

Explanation:

For a satellite in orbit around the Earth, the gravitational force provides the centripetal force that keeps the satellite in motion:

$G\frac{Mm}{r^2}=m\frac{v^2}{r}$

where

G is the gravitational constant

M is the Earth's mass

m is the satellite's mass

r is the distance between the satellite and the Earth's centre

v is the speed of the satellite

Re-arranging the equation, we write

$r = \frac{GM}{v^2}$

so we see from the equation that when the speed is higher, the distance from the Earth's centre is smaller, and when the speed is lower, the distance from the Earth's centre is larger.

Here, the second satellite orbit the Earth at a speed less than v: this means that its orbit will have a larger radius than the first satellite, so the correct answer is

c)At a distance greater than r

7 0

3 years ago

Guys please help me

Likurg_2 [28]

Answer:

1) $t=2.26\: s$