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Bad White [126]
3 years ago
15

What is the vertical asymptote

Mathematics
1 answer:
ddd [48]3 years ago
3 0

Answer:

Vertical asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function. It will be the red ones

Step-by-step explanation:

(They can also arise in other contexts, such as logarithms, but you'll almost certainly first encounter asymptotes in the context of rationals.)

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Can not be bothered to write the question so ima just attach it
stellarik [79]

Use desmos graphing calculator, for visuals. It's easy to use as well.

A is 0 (zero)

(1x1 + 2x1 - 3)

B) D ( lies on 1 on our x-axis)

C) This tells you to draw a line at zero on the y-axis, a horizontal line BTW & read off the x values, where the line touches the pink graph/diagram.

y=x^2+2x-3 is the similar to x^2+2x-3=0 because the letter y now represents zero. So, that's why we draw the line y=0 (a horizontal line at zero). Then, use it to find the x values.

Thus, x = - 3 & x = 1

Hope this helps!

6 0
2 years ago
Ray has 3 boxes of chocolates. Each box has 4 layers of chocolates. Each layer has 4 rows of 4 chocolates each. He distributes a
RSB [31]
I believe it is (3*4*4*4)/16=12
hopefully its right and it helped!
6 0
3 years ago
Read 2 more answers
X equals ??????????
Ymorist [56]
Answer: x = 18

explanation: the two angles are congruent bc so you can set the equation up as 9x - 40 = 5x + 32 and then solve for x

hope this helps :)
7 0
3 years ago
Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is −6. The distance between point A and point B is 15 units. What
xxTIMURxx [149]

Answer:

Distance between two points= √(x2-x1)²+(y2-y1)²

D= 15units

Let "k" be the y-coordinate of A

A(-6,k)

B(3,2)

15= √(3--6)²+(2-k)²

Taking square of both sides to eliminate the square root.

15²=(9)²+(2-k)²

225=81+4-4k+k²

k²-4k - 140=0

Using Quadratic Formula to evaluate

k= 14 or k=-10

The Possible coordinates of A are

(-6,14) or (-6,-10)

4 0
2 years ago
Solve x + 3y = 9. 3x – 3y = –13
Sloan [31]
Question \ 1) \ x + 3y = 9 


x=9-3y
 
  |Subtract \ 3y \ from \ both \ sides| 

Question \ 2) \ 3x - 3y = -13 


3(x-y)=-13
 
   |Factor \ out \ the \ common \ term \ 3|

x-y= \dfrac{13}{3}   |Divide \ both \ sides \ by \ 3|

x=- \dfrac{13}{3}+y  |Add \ y \ to \ both \ sides|

x=y- \dfrac{13}{3}  |Regroup \ terms|

7 0
3 years ago
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