Question

A certain shade of blue has a frequency of 7.05 × 1014 hz. What is the energy of exactly one photon of this light?

Answer 1

Energy of photon is equal to the product of Planck's constant and frequency.

The mathematical expression is given as :

$E = h\nu$

where,

E = energy of photon

h = Planck's constant i.e. $6.626 \times 10^{-34} Js$

$\nu$ = frequency

Put the given values of frequency and Planck's constant in above formula, we get

$E =6.626 \times 10^{-34} Js\times 7.05 \times 10^{14} Hz$

= $46.7133\times 10^{-20} Js Hz$

Since, Hz is equal to $second^{-1}$

Thus, energy of photon =  $46.7133 \times 10^{-20} J$ or $4.67133 \times 10^{-19} J$