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topjm [15]
3 years ago
13

You find a compound composed only of element "X" and hydrogen, and know that it is 91.26% element X by mass. Each molecule has 2

.67 times as many H atoms as X atoms. What is element X?
Chemistry
2 answers:
worty [1.4K]3 years ago
4 0
Since you know the ratio of atoms, you can start to put a formula togeter. The formula might look like:<span>
X<span>H2.67 
</span></span>but since atoms can't come in fractional amounts, we have to multiply the formula by some number in order to turn 2.67 into a whole #, while still maintaining the ratio. Multiplying 2.67 by 3 yields 8, so the most likely ratio in the molecule is

X3H8<span>so the ratio of 1:2.67 is still maintained. The mass percent tells you that out of every 100g of compound, 91.26g is element X, so the other 8.74g must be H. Dividing each mass by the number of moles in the formula gets us the molar mass of each element (approximately). DIviding 8.74g by 8 gets 1.09, roughly the molar mass of hydrogen. Dividing 91.26g by 3 gets us 30.4, roughly the molar mass of phosphorus. Element X is most likely phosphorus</span>
AlekseyPX3 years ago
3 0

Answer:

The element X is silicon.

Explanation:

Percentage of element X in compound molecule = 91.26%

Number of X element atom in a molecule = n

Number of hydrogen atom in a molecule = n × 2.67

Molecular formula of compound = H_{2.67n}X_{n}=H_{267}X_{100}

Let the atomic mass of element X = m

Molar mass of compound =267 g/mol+100m

Percentage of an element in a compound:

\%=\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100

91.26\%=\frac{100 m}{267 g/mol+100m}\times 100

m = 27.87 g/mol ≈ 28 g/mol

The element X is silicon.

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Yakvenalex [24]

Answer:

8.675 *10^10

Explanation:

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4 years ago
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A student wants to collect data during an experiment about the transfer of kinetic energy in a sample of water and ice. Which to
erastova [34]

Given what we know, the tool in question that will help the student collect data regarding the transfer of kinetic energy between water and ice would be a thermometer.

<h3>How does the thermometer measure kinetic energy?</h3>

It does not do so directly. However, kinetic energy in water molecules is reflected in the temperature of the water. When water molecules increase their kinetic energy and move more, they become hotter. Increased or decreased heat is an indirect way to measure the transfer of kinetic energy in water.

Therefore, given that the temperature of the water is a reflection of the transfer of kinetic energy happening, we can confirm that the tool that will help the student collect the data needed is a thermometer.

To learn more about kinetic energy visit:

brainly.com/question/999862?referrer=searchResults

3 0
3 years ago
What is responsible for the sharp decrease in ionization energy between the elements with 2 and 3 atomic number? 10 and 11?
PSYCHO15rus [73]
An extra shell, which means further distance between those electrons in the valence shell and the nucleus. Ionisation energy refers to the energy required to remove valence electrons. There will be more energy required if the valence electrons are closer to the nucleus that have a positive charge, because of more attraction. If there is an extra shell, there is further distance, less attraction and hence less energy required.
6 0
3 years ago
How many moles of zinc are needed to react with 45.60 moles of nitric acid?
uranmaximum [27]

Answer:

11.4 moles

Explanation:

Your chemical equation for the reaction of zinc and nitric acid will be

Zn  +  4 HNO₃  -->  Zn(NO₃)₂  +  2 NO₂  +  2 H₂O

To solve the problem, you need to use stoichiometry.  For every 1 mole of zinc, you will need 4 moles of nitric acid.  Divide 45.60 by 4.  Your answer should be 11.4 moles.

3 0
3 years ago
Carbon monoxide reacts with oxygen gas to form carbon dioxide according to the following chemical equation. 2CO(g)+O2(g)⟶2CO2(g)
igomit [66]

Answer:

38.8 mL

Explanation:

2CO(g) + O₂(g)⟶2CO₂(g)

Because pressure and temperature remain constant, we can <em>think of the moles ratios as volume ratios</em>. This means that 2mL of CO react with 1 mL of O₂ to produce 2 mL of CO₂.

Because the problem asks us to calculate the amount of oxygen gas unreacted, then CO is the limiting reactant. We <u>calculate the amount of O₂ that reacted</u>, from the available amount of CO:

82.4 mL CO * \frac{1mLO_{2}}{2mLCO} = 41.2 mL O₂

Thus, the oxygen gas remaining is:

80.0 mL - 41.2 mL = 38.8 mL O₂

3 0
3 years ago
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