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topjm [15]
3 years ago
13

You find a compound composed only of element "X" and hydrogen, and know that it is 91.26% element X by mass. Each molecule has 2

.67 times as many H atoms as X atoms. What is element X?
Chemistry
2 answers:
worty [1.4K]3 years ago
4 0
Since you know the ratio of atoms, you can start to put a formula togeter. The formula might look like:<span>
X<span>H2.67 
</span></span>but since atoms can't come in fractional amounts, we have to multiply the formula by some number in order to turn 2.67 into a whole #, while still maintaining the ratio. Multiplying 2.67 by 3 yields 8, so the most likely ratio in the molecule is

X3H8<span>so the ratio of 1:2.67 is still maintained. The mass percent tells you that out of every 100g of compound, 91.26g is element X, so the other 8.74g must be H. Dividing each mass by the number of moles in the formula gets us the molar mass of each element (approximately). DIviding 8.74g by 8 gets 1.09, roughly the molar mass of hydrogen. Dividing 91.26g by 3 gets us 30.4, roughly the molar mass of phosphorus. Element X is most likely phosphorus</span>
AlekseyPX3 years ago
3 0

Answer:

The element X is silicon.

Explanation:

Percentage of element X in compound molecule = 91.26%

Number of X element atom in a molecule = n

Number of hydrogen atom in a molecule = n × 2.67

Molecular formula of compound = H_{2.67n}X_{n}=H_{267}X_{100}

Let the atomic mass of element X = m

Molar mass of compound =267 g/mol+100m

Percentage of an element in a compound:

\%=\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100

91.26\%=\frac{100 m}{267 g/mol+100m}\times 100

m = 27.87 g/mol ≈ 28 g/mol

The element X is silicon.

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8 0
3 years ago
Read 2 more answers
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deff fn [24]

Answer:

c. 2 and 3

Explanation:

Ca(NO3)2 names calcium nitrate.

Ca metal, O, N - nonmetals, so Ca(NO3)2 is ionic compound.

It is solid and white.

4 0
3 years ago
what is the order of decreasing bond length for a C-C bond composed of the following molecular orbitals?I. sp^3 - sp^3II. sp^2 -
skelet666 [1.2K]

Answer:

The decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

Explanation:

Bond length is defined as average distance between two nuclei of  bonded atoms in a molecule.Bond length is inversely  proportional to the number of bonds present between two atoms.

\text{Bond length} \propto \frac{1}{\text{Number of bonds}}...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom. Bond energy is directly proportional to the number of bonds present between two atoms.

\text{Bond Energy} \propto \text{Number of bonds}..[2]

From [1] and [2]:

\text{Bond length} \propto \frac{1}{\text{Bond energy}}

C-C: sp_3 hybridized

C=C: sp_2 hybridized

C\equiv C: sp hybridized

Extent of overlapping of orbitals in these hybridization;

C\equiv C> C=C > C-C

Higher the overlapping of orbital more closer will be both atoms to each other and shorter will be the bond lenght.

So, the decreasing order of bond length in the carbon - carbon bonds will be:

C-C>C=C>C\equiv C

8 0
3 years ago
if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As
Black_prince [1.1K]
Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture 
Na₂SO₄ ---> 2 Na⁺ + SO₄³⁻

1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions 

the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
                                                         = 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol

NaCl ----> Na⁺ + Cl⁻ 
1 mol of NaCl gives 1 mol of Na⁺ ions
number of NaCl moles added = 1.20 M/1000 * 200 ml
                                               = 0.24 mol
number of Na⁺ ions from NaCl = 0.24 mol

total number of Na⁺ ions in the mixture = 0.16 mol + 0.24 mol = 0.4 mol
as stated the volumes are additive, 
therefore total volume  = 100 ml + 200 ml = 300 ml 
the concentration of Na⁺ ions = number of moles / volume 
                                              = 0.4 mol/ 0.3 dm³
concentration of Na⁺ = 1.33 mol/dm³
5 0
3 years ago
For the reaction of aqueous strontium chloride and lithium sulfate, write the balanced molecular equation
Igoryamba
SrCl2 + Li2(SO4) —> 2LiCl + Sr(SO4)
7 0
3 years ago
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