For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Answer:
<h2> The answer is </h2><h2> D. 8x^2+4xy</h2>
Step-by-step explanation:
We know that the expression for the perimeter is given as
P=2l+2B
now given that the value of the width is =2x
length= 4x
and the breadth=y
P=4x+2y
let us multiply both the length and the width with 2x we have
P=2x(4x+2y)
P=8x^2+4xy
the answer is
D. 8x^2+4xy
2:5
It can also be expressed as 2 to 5 or 2/5
Take Saturdays total of $620 and subtract Fridays total of $460 to get $160. Divide that by the difference of the number of pies sold on Friday and Saturday to get $8. Take the $8 and multiply by number of pies sold on Friday (20) to get $160. Take that number and subtract it from the total sold on Friday ($460) to get $300. Divide that by how many cakes were sold on Friday (30) and get $10.
So therefore:
Pies - $8 each
Cakes - $10 each
