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ikadub [295]
3 years ago
7

2.(06.01 MC)

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
I believe you meant x instead of 4

7 + (2+6) 2 = x
7 + (8)2 = x
7+16 = x
23 = x
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Artemon [7]
V=160......................

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3 years ago
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Simplify -6²/ 12 - 2(-7)​
Rasek [7]
The simplify is 11, -6²/ 12 - 2(-7)=11
6 0
4 years ago
On a hot summers day 262 people used the public swimming pool. The daily prices are 1.50 for children and 2.00 for adults. The r
ololo11 [35]
<h3>Answer:</h3>
  • 154 adults
  • 108 children
<h3>Step-by-step explanation:</h3>

Let x represent the number of adults who swam at the pool. Then (262-x) is the number of children. Multiplying these numbers by the corresponding admission charge will give the associated receipts. We are given the total of receipts, so we can write the equation ...

... 2.00x +1.50(262-x) = 470.00

... 0.50x +393.00 = 470.00 . . . . . simplify

... 0.50x = 77.00 . . . . . . . . . . . . . . .subtract 393

... 77.00/0.50 = x = 154 . . . . . . . . . divide by the coefficient of x

... (262-x) = 108 . . . . . . . . . . . . . . . .find the number of children admitted

8 0
3 years ago
It has been observed that electrical connectors manufactured by Jolt Electrical Supply Company last an average of 18.2 months an
Juli2301 [7.4K]

Answer:

340

Step-by-step explanation:

The first step is finding the percentage of those who fail within 19 months.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 18.2, \sigma = 1.7

The proportion is the pvalue of Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 18.2}{1.7}

Z = 0.47

Z = 0.47 has a pvalue of 0.6808.

Jolt is expected to replace 0.6808 of the connectors sold. Out of 500, that is, on average, 0.6808*500 = 340.

Jolt expects to replace, on average, 340 of the connectors sold.

4 0
3 years ago
Can I get some help :/ ?
serious [3.7K]
1.750
3.516540
4.354.2
5.3560
6.4.73
7.1277.2
8.4544
9.813000
10.0.02532
11.3160000
12.0.00335
13.26310
14. 918.7
15. 9320
16.8.42
17.45160000
18.0.005435
19.2450
20.656.9

Hope this helps!
4 0
3 years ago
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