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3 years ago

What Should be added To -6(-p-1) to get 3p³+5p²+6p-2?

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

Answer:

3p³ + 5p² - 8

Step-by-step explanation:

Given:

6p - 2

-6(-p-1) = 6p + 6

Subtract 6p + 6 from 3p³ + 5p² + 6p - 2 get your answer

= 3p³ + 5p² + 6p - 2 - (6p + 6)

= 3p³ + 5p² + 6p - 2 - 6p - 6

= 3p³ + 5p² - 8

3p³ + 5p² - 8 Should be added To -6(-p-1) to get 3p³+5p²+6p-2

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Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.

$2 cot(\frac{-9\pi}{2}) = 2 cot(\frac{9\pi}{2})$ Incorrect step

Because as per even/odd identity,

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3 years ago

What Should be added To -6(-p-1) to get 3p³+5p²+6p-2?​

What Should be added To -6(-p-1) to get 3p³+5p²+6p-2?