Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
No clue brother this one diff kit
Cell membranes are 50% protein, the proteins are responsible for many biological processes. If the proteins were absent the membrane could not carry out it's intended purpose.
Answer:
52.5 J
Explanation:
Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.
i.e W = F × s
It is a scalar quantity and measured in Joules (J).
Given that: F = 35.0 N and s = 1.50 m, then;
W = F × s
W = 35.0 × 1.5
= 52.5 J
Therefore, the work done on the sleigh by Samuel is 52.5 J.
Answer:
Vf = 44.27 m/s
Explanation:
When a ball is dropped it is acted upon by gravitational force under free fall motion. So, in order to find its final speed we use 2rd equation of motion, as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height lost = 100 m
Vf = Final Velocity = ?
Vi = Initial velocity = 0 m/s (Since, ball starts from rest)
Therefore,
(2)(9.8 m/s²)(100 m) = Vf² - (0 m/s)²
Vf = √(1960 m²/s²)
<u>Vf = 44.27 m/s</u>
